After plotting the data for one trial as outlined in the procedure, the following trendlines are obtained: Cooling Curve: y = -0.102x + 78.49 Freezing Curve: y= -0.006x + 63.06 Calculate the freezing point ("C) from this data. Give your answer to one decimal place. Your Answer:

After plotting the data for one trial as outlined in the procedure, the following trendlines are obtained: Cooling Curve: y = -0.102x + 78.49 Freezing Curve: y= -0.006x + 63.06 Calculate the freezing point ("C) from this data. Give your answer to one decimal place. Your Answer:

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter11: Solutions

Section: Chapter Questions

Problem 47P

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

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After plotting the data for one trial as outlined in the procedure, the following
trendlines are obtained:
Cooling Curve: y = -0.102x + 78.49
Freezing Curve: y= -0.006x+ 63.06
Calculate the freezing point ("C) from this data. Give your answer to one decimal
place.
Your Answer:

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