age - Blinn College Önline sd21.blinn.edu s the weight of the same item four times with the following results. Complete the following table to determine how they should sion? (Mass-Avg Mass] Standard Deviation Average Mass Report All Numbers as Significant Mass Repart to 1 Sig Fig Report to Correct SigFigs N' i=1(T;- 7)2 N 1 12.3569 g Try 1: / 1.6E-7 12.3572 g Try 1: / 1E-8 i=1 is the sum of the (Mass - Avg Try 1: 12.3573 Mass)? 12.3583 g Try 1: / 1E-6 N- 1 is the number of Trials Info minus 1 Try 1: 2.5E-7 12.3568 g Info NG Info be 12.3573 f, a Gp 3. 3. 3.

age - Blinn College Önline sd21.blinn.edu s the weight of the same item four times with the following results. Complete the following table to determine how they should sion? (Mass-Avg Mass] Standard Deviation Average Mass Report All Numbers as Significant Mass Repart to 1 Sig Fig Report to Correct SigFigs N' i=1(T;- 7)2 N 1 12.3569 g Try 1: / 1.6E-7 12.3572 g Try 1: / 1E-8 i=1 is the sum of the (Mass - Avg Try 1: 12.3573 Mass)? 12.3583 g Try 1: / 1E-6 N- 1 is the number of Trials Info minus 1 Try 1: 2.5E-7 12.3568 g Info NG Info be 12.3573 f, a Gp 3. 3. 3.

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

ChapterA1: Evaluation Of Analytical Data

Section: Chapter Questions

Problem A1.9QAP

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Data Given. no Trial 3 information needed
A volumetric calcium analysis on triplicate samples of the blood serum of a patient believed to be suffering from a hyperparathyroid condition produced the following data: mmol Ca/L = 3.55, 3.65, 3.14. What is the 95% confidence interval for the mean of the data, assuming(a) No prior information about the precision of the analysis?(b) s → σ = 0.056 mmol Ca/L?
using exactly 5.00 mL of 0.0400 M stock CuSO4 solution. Add 100 mL of water. Data for Part IMass of empty dish: 32.470 g empty dishVolume of 0.0400 M solution: 5.00 mL CuSO4 solution.Mass of dish and 0.0400 M solution: 37.497 g dish and solutionMass of dish and CuSO4 solid: 32.503 g dish and CuSO4 solidCalculations for Part I1. Calculate the mass of solution? 5.027 g 2. Calculate the mass of solid CuSO4 dissolved in the solution? 0.033 g 3. Calculate the number of moles of solid CuSO4 dissolved in the solution? 2.07 x 10-4 mol4. Calculate the mass of water evaporated from the solution? 0.0414 M5. Calculate the density of solution, (g solution/mL solution)?6. Calculate the % by mass, CuSO4 in solution (100 x g CuSO4/g solution)?7. Calculate the molality of solution (moles CuSO4/kg solvent)?8. Calculate the molarity of solution (moles CuSO4/L solution)?9. Given that the true molarity is 0.0400 M, calculate the percent error…
Which procedure(s) decrease(s) the random error of a measure-ment: (1) taking the average of more measurements; (2) calibrat-ing the instrument; (3) taking fewer measurements? Explain
using exactly 5.00 mL of 0.0400 M stock CuSO4 solution. Add 100 mL of water. Data for Part IMass of empty dish: 32.470 g empty dishVolume of 0.0400 M solution: 5.00 mL CuSO4 solution.Mass of dish and 0.0400 M solution: 37.497 g dish and solutionMass of dish and CuSO4 solid: 32.503 g dish and CuSO4 solidCalculations for Part I1. Calculate the mass of solution2. Calculate the mass of solid CuSO4 dissolved in the solution.3. Calculate the number of moles of solid CuSO4 dissolved in the solution.4. Calculate the mass of water evaporated from the solution.5. Calculate the density of solution, (g solution/mL solution).6. Calculate the % by mass, CuSO4 in solution (100 x g CuSO4/g solution).7. Calculate the molality of solution (moles CuSO4/kg solvent).8. Calculate the molarity of solution (moles CuSO4/L solution).9. Given that the true molarity is 0.0400 M, calculate the percent error of your result.
3. A student weighed an unknown mass directly on an electronic balance of intermediate sensitivity, and got a result of 28.774 g. The student then realized a mistake had been made, and weighed the same unknown by difference on the same balance with the following results:Mass of beaker plus unknown = 59.121 g.Mass of empty beaker = 30.346 g.When the sensitivity of the balance is taken into account, the two values obtained for the unknown mass are considered to be:a. Differentb. The SameExplain your answer.
1. Calculate the experimental density of a salt solution and the percent error (same as relative error percent) using some or all the data given below. solubility of NaCl salt in water: 0.357 g/mLmass of empty graduated cylinder: 25.19g mass of graduated cylinder + salt solution: 30.47g total volume of salt solution: 4.98 mLtrue density of salt solution: 1.07 g/mL
Round 0.221 to one sig. Fig
Given the following data forMass of test tube, beaker and cyclohexane = 100.17 gMass of test tube and beaker = 84.07 gFreezing point of cyclohexane = 6.59 oCMass of weighing paper + naphthalene =1.080 gMass of weighing paper = 0.928 gFreezing point solution = 5.11oCKf = 20.8oC/mDetermine the followinga. mass of cyclohexane in g (2 decimal places); _____b. mass of naphthalene in g (4 decimal places); _____c. freezing point depression (2 decimal places); _____d. molality of solution (3 significant figures); _____e. moles of naphthalene (3 significant figures); _____f. molar mass of naphthalene, experimentally (3 significant figures); _____g. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); ____