Aldehydes are easily converted (oxidised) to form carboxylic acids. Ketones, on the other hand, do not oxidise to form carboxylic acids. Suggest a reason why this is so.

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter28: Atomic Spectroscopy
Section: Chapter Questions
Problem 28.2QAP
icon
Related questions
Question

a) Aldehydes are easily converted (oxidised) to form carboxylic acids.
Ketones, on the other hand, do not oxidise to form carboxylic acids.
Suggest a reason why this is so.

An experiment was conducted to determine the concentration of
glucose in Macadamia flower nectar.
100 grams of Macadamia flowers was extracted with 500 mL of water.
Using an Optical Rotation detector a standard curve was produced using
pure glucose.
Optical Rotation Angle (OR)
1.6
1.4
1.2
1
0.8
0.6
0.4
Glucose Concentration (mM) vs Optical Rotation Angle
OR = 0.0341 [mM glucose ] +0.0017.
5
10
15
25
30
Glucose Concentration (mm)
20
35
40
45
A sample of nectar extract was analysed on the optical rotation detector
and an angle of 0.192⁰ was measured.
Determine the concentration of glucose in the solution using the
equation of the standard curve graph.
Transcribed Image Text:An experiment was conducted to determine the concentration of glucose in Macadamia flower nectar. 100 grams of Macadamia flowers was extracted with 500 mL of water. Using an Optical Rotation detector a standard curve was produced using pure glucose. Optical Rotation Angle (OR) 1.6 1.4 1.2 1 0.8 0.6 0.4 Glucose Concentration (mM) vs Optical Rotation Angle OR = 0.0341 [mM glucose ] +0.0017. 5 10 15 25 30 Glucose Concentration (mm) 20 35 40 45 A sample of nectar extract was analysed on the optical rotation detector and an angle of 0.192⁰ was measured. Determine the concentration of glucose in the solution using the equation of the standard curve graph.
Knowing the molecular weight of glucose is 180 grams per mole
determine the concentration of glucose in the 100 grams of macadamia
flowers as grams glucose per gram macadamia flowers.
Transcribed Image Text:Knowing the molecular weight of glucose is 180 grams per mole determine the concentration of glucose in the 100 grams of macadamia flowers as grams glucose per gram macadamia flowers.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Carboxylic Acids and their Derivatives
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:
9781285640686
Author:
Skoog
Publisher:
Cengage
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305580350
Author:
William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:
Cengage Learning
EBK A SMALL SCALE APPROACH TO ORGANIC L
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:
9781305446021
Author:
Lampman
Publisher:
CENGAGE LEARNING - CONSIGNMENT
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781285199023
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning