Aluminum reacts with iron (III) oxide to form aluminum oxide and iron metal in the following reaction:  2  Al  +   1  Fe2O3  →    1  Al2O3  +   2  Fe   Using the answer choices below, which set up would correctly complete the work for determining how many grams of aluminum are needed to produce 58.0 g of iron metal? 58.0 g Fe   x    1 mole Fe       X   ????   X      26.98 g Al                  55.85 g Fe                                1 mol Al   MM Al: 26.98 g/mol MM Fe2O3: 159.7 g/mol MM Al2O3: 101.96 g/mol MM Fe: 55.85 g/mol a 1 mol Al/ 26.98 g Al b 1 mol Fe/ 55.85 g Fe c 2 mol Al/ 2 mol Fe d 2 mol Fe/ 2 mol Al

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".