Ammonium nitrate has been used as a high explosive because it is unstable and decomposes into several gaseous substances. The rapid expansion of the gaseous substances produc the explosive force. NH,NO3 (8) → N2(g) + O2 (9) + H20(g) Calculate the mass of each product gas if 47.4 g of ammonium nitrate reacts. | g N2 g O2 | g H2O

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter3: Mass Relations In Chemistry; Stoichiometry
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Problem 67QAP: When potassium chlorate is subjected to high temperatures, it decomposes into potassium chloride and...
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Ammonium nitrate has been used as a high explosive because it is unstable and decomposes into several gaseous substances. The rapid expansion of the gaseous substances produces
the explosive force.
NH,NO3 (8) → N2 (g)+ O2 (g) + H2O(g)
Calculate the mass of each product gas if 47.4 g of ammonium nitrate reacts.
g N2
g O2
g H2O
Transcribed Image Text:Ammonium nitrate has been used as a high explosive because it is unstable and decomposes into several gaseous substances. The rapid expansion of the gaseous substances produces the explosive force. NH,NO3 (8) → N2 (g)+ O2 (g) + H2O(g) Calculate the mass of each product gas if 47.4 g of ammonium nitrate reacts. g N2 g O2 g H2O
Expert Solution
Step 1

Mole concept: Numerically It is the number of grams of a substance divided by the molar mass of the compound.

The formula to calculate the number of moles(n) is 

n=mMor. m =n×M

where m = mass of the substance given in gram.

M = molar mass of the substance in g/mol.

 

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