An air-gap parallel-plate capacitor that has a plate area of 1.20 m2 and a separation of 1.40 mm is charged to 90 V.(a) What is the electric field between the plates?kV/m(b) What is the electric energy density between the plates?|mJ/m3(c) Find the total energy by multiplying your answer from Part (b) by the volume between the plates.(d) Determine the capacitance of this arrangement.nF(e) Calculate the total energy from U = V2CV2, and compare your answer with your result from Part (c).

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An air-gap parallel-plate capacitor that has a plate area of 1.20 m2 and a separation of 1.40 mm is charged to 90 V. (a) What is the electric field between the plates? kV/m (b) What is the electric energy density between the plates? m)/m3 (c) Find the total energy by multiplying your answer from Part (b) by the volume between the plates.

An air-gap parallel-plate capacitor that has a plate area of 1.20 m2 and a separation of 1.40 mm is charged to 90 V. (a) What is the electric field between the plates? kV/m (b) What is the electric energy density between the plates? m)/m3 (c) Find the total energy by multiplying your answer from Part (b) by the volume between the plates.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 66P: A parallel-plate capacitor in air has a plate separation of 1.50 cm and a plate area of 25.0 cm2....

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