An aluminum alloy [E = 69 GPa; v = 0.33; a = 23.0 x 10-6/°C] plate is subjected to a tensile load P. The plate has a depth of d = 215 mm, a cross-sectional area of A = 5100 mm2, and a length of L = 3.9 m. The initial longitudinal normal strain in the plate is zero. After load P is applied and the temperature of the plate has been increased by AT = 53°C, the longitudinal normal strain in the plate is found to be 2320 με. Determine: (a) the magnitude of load P. (b) the change in plate depth Ad. L Answer: (a) P = i (b) Δd = = i d KN mm

Steel Design (Activate Learning with these NEW titles from Engineering!)
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Chapter1: Introduction
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Problem 1.5.4P: A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the...
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An aluminum alloy [E = 69 GPa; v = 0.33; a = 23.0 x 10-6/°C] plate is subjected to a tensile load P. The plate has a depth of d = 215 mm,
a cross-sectional area of A = 5100 mm2, and a length of L = 3.9 m. The initial longitudinal normal strain in the plate is zero. After load P
is applied and the temperature of the plate has been increased by AT = 53°C, the longitudinal normal strain in the plate is found to be
2320 με. Determine:
(a) the magnitude of load P.
(b) the change in plate depth Ad.
L
Answer:
(a) P = i
(b) Δd = = i
d
KN
mm
Transcribed Image Text:An aluminum alloy [E = 69 GPa; v = 0.33; a = 23.0 x 10-6/°C] plate is subjected to a tensile load P. The plate has a depth of d = 215 mm, a cross-sectional area of A = 5100 mm2, and a length of L = 3.9 m. The initial longitudinal normal strain in the plate is zero. After load P is applied and the temperature of the plate has been increased by AT = 53°C, the longitudinal normal strain in the plate is found to be 2320 με. Determine: (a) the magnitude of load P. (b) the change in plate depth Ad. L Answer: (a) P = i (b) Δd = = i d KN mm
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