An aqueous solution is prepared by dissolving 0.415g of KMnO4 in 250.0mL of water. This solution is then diluted by taking a 25.0mL aliquot (sample) and diluting it to 100.0mL with water. A third solution is then prepared by taking 10.0mL of the diluted solution and further diluting it to 50.0mL with water. Show how to determine (and then calculate) the molarity of each solution (the 3 different solutions prepared). Use the factor-label (Conversion-factor) method for all conversions. Be sure to include units where applicable. All numeric answers must be round to significant figures.

Question
Asked May 1, 2019

An aqueous solution is prepared by dissolving 0.415g of KMnO4 in 250.0mL of water. This solution is then diluted by taking a 25.0mL aliquot (sample) and diluting it to 100.0mL with water. A third solution is then prepared by taking 10.0mL of the diluted solution and further diluting it to 50.0mL with water. Show how to determine (and then calculate) the molarity of each solution (the 3 different solutions prepared). Use the factor-label (Conversion-factor) method for all conversions. Be sure to include units where applicable. All numeric answers must be round to significant figures. 

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Expert Answer

Step 1

First Solution

An aqueous solution is prepared by dissolving 0.415 g of KMnO4 in 250 mL. The molarity of the solution can be calculated as,

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Step 2

Second Solution

From the above solution, 25 mL (V1) of sample is taken which is having a molarity of 0.010 M (M1) and is diluted to 100 mL (V2). It is required to calculate the molarity of the diluted sample, which can be calculated as,

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Step 3

Third Solution

Now from the second solution, 10 mL (V2) is taken which is having a molarity of 0.0025 M (M2) and is d...

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