An electron is accelerated from rest between two parallel plates that are seperated by 2.90 cm. The potential difference between the two plates is 1.13×103 V. If the electron travels from the negative plate to the positive plate, what will be the speed of the electron as it exits through a small hole in the positive plate? 3.39×106 m/s 2.13×107 m/s 1.85×107 m/s 1.99×107 m/s
An electron is accelerated from rest between two parallel plates that are seperated by 2.90 cm. The potential difference between the two plates is 1.13×103 V. If the electron travels from the negative plate to the positive plate, what will be the speed of the electron as it exits through a small hole in the positive plate? 3.39×106 m/s 2.13×107 m/s 1.85×107 m/s 1.99×107 m/s
Chapter7: Electric Potential
Section: Chapter Questions
Problem 37P: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50104...
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An electron is accelerated from rest between two parallel plates that are seperated by 2.90 cm. The potential difference between the two plates is 1.13×103 V. If the electron travels from the negative plate to the positive plate, what will be the speed of the electron as it exits through a small hole in the positive plate?
3.39×106 m/s
2.13×107 m/s
1.85×107 m/s
1.99×107 m/s
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