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- The "spring-like effect" in a golf club could be determined by measuring the coefficient of restitution (the ratio of the outbound velocity to the inbound velocity of a golf ball fired at the clubhead). Twelve randomly selected drivers produced by two clubmakers are tested and the coefficient of restitution measured. The data follow: Club 1: 0.8406, 0.8104, 0.8234, 0.8198, 0.8235, 0.8562, 0.8123, 0.7976, 0.8184, 0.8265, 0.7773, 0.7871 Club 2: 0.8305, 0.7905, 0.8352, 0.8380, 0.8145, 0.8465, 0.8244, 0.8014, 0.8309, 0.8405, 0.8256, 0.8476 Test the hypothesis that both brands of ball have equal mean overall distance. Use α = 0.05 and assume equal variances. Question: Reject H0 if t0 < ___ or if t0 > ___.Data from a recent year showed that 55% of the tens of thousands of applicants to a certain program were accepted. A company that trains applicants claimed that 135 of the 240 students, it trained that year were accepted. Assume these trainees were representative of the population of applicants. Has the company demonstrated a real improvement over the average? What is the P-value?The quality control engineer at Palmer Industries is interested in estimating the tensile strength of steel wire based on its outside diameter and the amount of molybdenum in the steel. As an experiment, she selected 25 pieces of wire, measured the outside diameters, and determined the molybdenum content. Then she measured the tensile strength of each piece. The results of the first four are recorded in the table. Tensile Strength Outside Diameter Amount of Molybdenum Place (PSI ) Y (mm) X1 (Units) X2 A 11 0.3 6 B 9 0.2 5 C 16 0.4 8 D 12 0.3 7 Using a statistical software package, the QC engineer determined the multiple regression equation to be Y’=-0.5+20X1+1X2. a) Based on the equation, what is the estimated tensile strength of a steel wire having an outside diameter of .35 mm and 6.4 units of molybdenum? b) Interpret the value of b1 in the equation.
- A study was done to compare the birth weight of newborn babies from the general population to a group of 24 babies born to mothers who smoked during pregnancy. The researcher was testing her prediction of an average lower birth weight for babies born to smokers. The mean birth weight in the population was reported to be 3.5 kg and birth weight in the sample was M = 3.0 kg. Results from the t-test used in data analysis showed a t-value = 5.35, p = .02. No calculations are required here. Type in your answers to the following questions in the space below. 1) which of the 3 t-tests is the proper one to use? 2) Write the Null and Alternative Hypotheses for this study in a sentence, including the value of mu. 3) Write an APA conclusion for this study to report the results. This sentence should include the IV and DV, significance, APA stats, and the M.your car is more crowded than you think. table 5.8 reports results from a 1969 personal transportation survey on "home-to-work" trips in metropolitan areas. show that the average number of riders in the car of a typical commuter is 1.9.Assuming that the data are normally distributed, A. Determine the z-score such that the area to its right is 17%. z = B. Determine the z-score such that the area to its left is 95%. z =
- IQ scores are normally-distributed with μ=100 and σ=15. What raw score would someone need to get in order to have a z-score of 0.89? Report your answer to 2 decimal places.The table below shows the results from the specific gravity (S.G.) test performed in a soil laboratory including twenty samples of sand. Determine the Coefficient of Quartile Variation.A new cream that advertises that it can reduce wrinkles and improve skin was subject to a recent study. A sample of 60 women over the age of 50 used the new cream for 6 months. Of those 60 women, 50 of them reported skin improvement(as judged by a dermatologist). Is this evidence that the cream will improve the skin of more than 40% of women over the age of 50? Test using α=0.05 test statistics z=? rejection region z>? The final conclustion is A. We can reject the null hypothesis that p=0.4 and accept that p>0.4 That is, the cream can improve the skin of more than 40% of women over 50.B. There is not sufficient evidence to reject the null hypothesis that p=0.4 That is, there is not sufficient evidence to reject that the cream can improve the skin of more than 40% of women over 50.
- The article “Effect of Internal Gas Pressure on the Com- pression Strength of Beverage Cans and Plastic Bottles” (J. of Testing and Evaluation, 1993: 129–131) includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberry drink and another sample filled with cola. Does the data suggest that the extra carbonation of cola results in a higher average compression strength? Base your answer on a P-value. What assumptions are necessary for your analysis? ( use ? = 0.01 )Sulfur dioxide (SO2) pollution is a known cause for corrosion of exposed steel. To document this effect in actual conditions, steel weight loss (gm/m3/yr) was measured at 36 locations in a large city, along with the rate at which SO2 was deposited (mg/m2/day). Perform a two-sided test of H0: ρ = 0.800, with α = 0.01. SO2 Loss 22.6 580 26.1 563 19.1 339 17.2 346 25 623 16.8 420 42.7 951 30.4 794 17.9 461 30.4 757 27.8 573 27.8 656 33 990 14.2 551 37.4 856 16.2 443 27.7 802 22.7 657 21 495 15.8 496 13.7 353 24.7 724 23.7 602 30.7 639 33.5 813 30.2 770 20.1 556 22.8 557 39.9 1001 15.5 432 40.4 940 27.9 687 39.4 919 25.1 590 28.6 640 29.7 702The solid black line in the figure below shows data from Vienna, which started requiring face masks on April 6, 2020. The dashed black line plots data from a nearby Salzburg, that did not implement a face mask requirement. Based on the data in the figure, estimate the impact of face masks on the cumulative number of Covid-19 cases in Vienna? Express your answer as a percent.