An object is launched at 38.6 meters per second (m/s) from an initial height of 2.6-meters. The equation for at time t seconds after launch is (t) = -4.9t2+38.6t+ 2.6. /hat is the height of the object 2.5 seconds after launch? eight is 68.5 meters hat is the height of the object 4 seconds after launch? eight is 78.6 meters hat is the height of the object 5.5 seconds after launch? eight is 63.4 meters

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter4: Complex Numbers
Section: Chapter Questions
Problem 22T
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Round all answers to two decimal places.
An object is launched at 38.6 meters per second (m/s) from an initial height of 2.6-meters. The equation for the object's height h in meters
at time t seconds after launch is
h(t) = -4.9t2+38.6t + 2.6
What is the height of the object 2.5 seconds after launch?
Height is 68.5
meters
What is the height of the object 4 seconds after launch?
Height is 78.6
meters
What is the height of the object 5.5 seconds after launch?
Height is 63.4
meters
Your last answer was interpreted as follows:
68.5
Your last answer was interpreted as follows:
78.6
Your last answer was interpreted as follows:
63.4
Transcribed Image Text:Round all answers to two decimal places. An object is launched at 38.6 meters per second (m/s) from an initial height of 2.6-meters. The equation for the object's height h in meters at time t seconds after launch is h(t) = -4.9t2+38.6t + 2.6 What is the height of the object 2.5 seconds after launch? Height is 68.5 meters What is the height of the object 4 seconds after launch? Height is 78.6 meters What is the height of the object 5.5 seconds after launch? Height is 63.4 meters Your last answer was interpreted as follows: 68.5 Your last answer was interpreted as follows: 78.6 Your last answer was interpreted as follows: 63.4
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