# An object thrown vertically upward from the surface of a celestial body at a velocity of 12 m/s reaches a height of s-0.2t12t meters in t seconds.a. Determine the velocity v of the object after t seconds.b. When does the object reach its highest point?c. What is the height of the object at the highest point?d. When does the object strike the ground?e. With what velocity does the object strike the ground?f. On what intervals is the speed increasing?

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Step 1

The given equation is s = –0.2t2 + 12t and the velocity is v =12 m/s.

a.

Obtain the velocity v of the object after t seconds.

Differentiate s = –0.2t2 + 12t with respect to t as follows.

Step 2

b.

It is known that, if the object attains the maximum then the velocity becomes zero.

Step 3

c.

Find the height of the objec...

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