An oil storage tank having a diameter of 30 m is located 3 m below the surface of a deposit of 23 m thick clay. A firm stratum underlies the clay. The water table is at the ground surface and the net foundation pressure is calculated to be 120 kN/m?. The average value of mv for the clay is 0.14 m/MN. The undrained value of Young's modulus (Ea) is estimated to be 40 MN/m?. Determine the total (immediate + consolidation) settlement under the center of the tank. Use a Skempton-Bjerrum correction factor of 0.7 for consolidation settlement.

Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN:9781305081550
Author:Braja M. Das
Publisher:Braja M. Das
Chapter8: Mat Foundations
Section: Chapter Questions
Problem 8.7P
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An oil storage tank having a diameter of 30 m is located 3 m below the surface of a deposit of
23 m thick clay. A firm stratum underlies the clay. The water table is at the ground surface and
the net foundation pressure is calculated to be 120 kN/m². The average value of mv for the clay
is 0.14 m/MN. The undrained value of Young's modulus (Ea) is estimated to be 40 MN/m?.
Determine the total (immediate + consolidation) settlement under the center of the tank. Use a
Skempton-Bjerrum correction factor of 0.7 for consolidation settlement.
(Hint: The clay layer below the tank may be divided into 4 sublayers.)
1.0
1.0
L= lengih
0.9
A 0.9
0.5
0.8
0.7
0.8
5
10
15
20
DIB
0.6
20
UB
0.5
10
1.5
0.4
2
0.3
. 1.0
1.5
1
Circle
0.2
0.
0.1
0.0
0.1
02 0.5 1 2
5 10 20
1 2 3 4 5 6 7 8
50 100
1000
Transcribed Image Text:An oil storage tank having a diameter of 30 m is located 3 m below the surface of a deposit of 23 m thick clay. A firm stratum underlies the clay. The water table is at the ground surface and the net foundation pressure is calculated to be 120 kN/m². The average value of mv for the clay is 0.14 m/MN. The undrained value of Young's modulus (Ea) is estimated to be 40 MN/m?. Determine the total (immediate + consolidation) settlement under the center of the tank. Use a Skempton-Bjerrum correction factor of 0.7 for consolidation settlement. (Hint: The clay layer below the tank may be divided into 4 sublayers.) 1.0 1.0 L= lengih 0.9 A 0.9 0.5 0.8 0.7 0.8 5 10 15 20 DIB 0.6 20 UB 0.5 10 1.5 0.4 2 0.3 . 1.0 1.5 1 Circle 0.2 0. 0.1 0.0 0.1 02 0.5 1 2 5 10 20 1 2 3 4 5 6 7 8 50 100 1000
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