An unknown hydrocarbon has a molecular ion peak at m/e = 84, with a relative intensity of 31.3. The M+1 peak has a relative intensity of 2.06, and the M+2 peak has a relative intensity of 0.08. What is the molecular formula of this substance? Answer is C6H12 but how?

An unknown hydrocarbon has a molecular ion peak at m/e = 84, with a relative intensity of 31.3. The M+1 peak has a relative intensity of 2.06, and the M+2 peak has a relative intensity of 0.08. What is the molecular formula of this substance? Answer is C6H12 but how?

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter14: Mass Spectrometry

Section: Chapter Questions

Problem 14.24P

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Concept explainers

UV Visible Spectroscopy

Spectroscopy refers to the absorption or emission of light or other radiations by matter. When a substance or chemical absorbs light or radiation, they reach an excited state followed by de-excitation or emission of the light or radiation forming distinct spectra. UV-visible spectroscopy or ultraviolet-visible refers to the absorption and emission in the ultraviolet and visible regions of the electromagnetic spectrum.

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Answer is C₆H₁₂ but how?

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