As network consultant for CSC311 IT Solutions, you are tasked with setting up an IP addressing structure using the following information: 1. You are provided with the main network, 192.168.10.0/24 from which you must create 3 VLSM subnets, as described in the topology diagram below. 2. The Default gateways for each network (A & B) will be the last valid IP Address. It will be the gig0/0 port on the router, which is the port connected to the network. 3. List the IP addresses and subnet masks of WAN Serial Interface ports se0/0 4. ServA through ServC will need to be assigned the first three (3) valid network addresses. 5. List the IP addresses, Subnet mask, and Gateway of the first and last hosts in BOTH Network 1 AND Network 2. Network #1 Hosts start at the 10th valid address. 10 Hosts ServA 22 R2 R1 ServB ServC 40 Hosts
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- An ISP is granted a block of addresses starting with 150.80.0.0/14 . The ISP wants to distribute these blocks to customers as follows:A- the first group has 50 customers, each needs 1024 IP addresses. B- the second group has 4 customers, each needs 512 IP addressesC- the third group has 64 customers, each needs 16 IP addressesSo, Design all the subnets? And find the amount of available IPs after all allocations.When you create a VPC. you provide the set of private IP addresses that you want instances in your VPC to use. You specify this set of addresses as a Classless Inter-Domain Routing (CIDR) black Subnets are a sul 1) How subnets and CIDR blocks used in a VPC? What are the architectural best practices for that? 2) A VPC with CIDR /22 includes 1.024 total IP addresses. However, this is not the total available IPs. What is a total number? and why is it less?You have been given the network address 192.168.9.0/24 to subnet and provide the IP addressing for the network shown in the Topology Diagram. The network has the following addressing requirements: The BRANCH1 LAN 1 will require 10 host IP The BRANCH1 LAN 2 will require 11 host IP The BRANCH2 LAN 1 will require 14 host IP The BRANCH2 LAN 2 will require 14 host IP The HQ LAN will require 27 host IP The link from HQ to BRANCH1 will require an IP address for each end of the The link from HQ to BRANCH2 will require an IP address for each end of the
- Your company has been assigned the following IP address by IANA: 135.120.0.0. Design a network thatconsists of 1000 subnetworks with each subnetwork having up to 60 hosts.(a) What address class is it? ______________________________________Express this IP address in the binary form: ______________________________________________(b) What is the network mask associated with this IP address? Write the mask in the decimal, binary andprefix form. Mask in decimal ___________________________________________________Mask in binary ___________________________________________________Mask in prefix form ___________________________________________________(c) Perform calculations below to check if this network can be designed. Show your calculations. (d) What is the subnetwork mask? Write the subnetwork mask in the decimal, binary and prefix form. Mask in decimal ___________________________________________________Mask in binary ___________________________________________________Mask in prefix form…You are assigned a network address 132.27.120.0/27. You want to create 2 subnets. For each subset, please give the network address, broadcast address, the lowest IP address, and the highest IP address for hosts? All the addresses should be in this format: x.x.x.x/xAn enterprise wants to use a network infrastructure that complies with the class B IP addressing template given below. The network part of this is the internet service provider (ISP) appointed by. According to this: a) How many subnets can this business create within itself? b) The maximum number of hosts in each subnet (LAN) can you take? c) Let one of these subnets be given as follows: subnet 1 : 10000010.00110010.00000100.00000000 Does the computer with IP address 130.50.7.139 belong to this subnet? Show your work and reasoning for each option.
- Let’s consider you have a Class C IP address 204.15.5.0/24. You have to determine whether it is possible to createfollowing network with the given IP address? If yes, what could be the possible ranges of IP addresses for thesubnetworks? Let’s consider the above network. If you are using VLSM /CIDR, determine what subnet mask numbers allow therequired number of hosts.Consider the following non-default subnet masks: (a) 255.255.248.0, (b) 255.128.0.0 . To which IP address class do they pertain?Write down the following in CIDR notation: (a) IP: 150.160.170.180, Subnet Mask:255.255.224.0; (b) IP: 75.80.85.90, Subnet Mask: 255.252.0.0 Three stations A, B, C and D are connected to a common Ethernet hub. Their IPaddresses and subnet mask are respectively: 200.100.50.67, 255.255.255.252;200.100.50.7, 255.255.255.248; 200.100.50.138, 255.255.255.240 and 200.100.50.1,255.255.255.254. Determine which among these stations can communicate with eachother. You need to show all detailed workings.Assume that you have two computers and a router (default gateway) that have the following TCP/IP configuration and that Computer A wants to send data to Computer E. Match the addresses that will be used in the IP packet and the ethernet frame sent from Computer A. Computer A IP address: 178.23.43.12 Netmask: 255.255.0.0 Default gateway address: 178.23.17.1 MAC Address: 34:2A:C6:C6:55:C3 Computer E IP address: 178.23.54.23 Netmask: 255.255.0.0 Default gateway address: 178.23.10.1 MAC Address: 34:2A:C6:76:3E:12 Default Gateway MAC Address: 65:D3:C9:11:C5:99 Items to Match: IP packet Source IP address: IP packet Destination IP address: Ethernet frame Source MAC address Ethernet frame Destination MAC address Possible Values: 178.23.17.1 178.23.10.1 178.23.43.12 178.23.54.23 34:2A:C6:C6:55:C3 65:D3:C9:11:C5:99 34:2A:C6:76:3E:12
- As the network engineer, you are asked to design an IP subnet plan that calls for 3subnets. The largest subnet needs a minimum of 52 hosts. Management requires that a single mask must be used throughout the Class C network. Which of the following is a private IP network and mask that would meet the requirements? A) 192.168.0.0 / 255.255.255.192 B) 192.168.0.0 / 255.255.255.224 C) 192.168.0.0 / 255.255.255.240 D) 192.168.0.0 / 255.255.255.248 Please explain the answerAttempt all Questions:- Part 1) Assign IP address configuration to the S2 server: part 1 question) Write IP-Address, Net mask and Default gateway. Part 2) To assign an IP address to the subnet A and to the subnet B you to have subdivide the network 169.1.96.0/19. Please choose a new netmask that subdivide the given network into atleast 3 (one for future use) subnetworks. You want to have a maximum amount of computer in each subnetwork. part 2 question) Write Net-mask (decimal dotted notation), your subnet A IP Address, Your subnet B IP Address, IP address R2 eth1 and IP Address R2 eth2. Part 3) Write down routing table of R1 (Routing table should include Destination, Next hoop and interface) Part 4) Write down routing table of R3 (Routing table should include Destination, Next hoop and interface) You are planning the network of a small company. The network has the address \( 169.1 .0 .0 / 16 . \) T some structure subnetGiven the IP address 180.15.128.0/20. Now, using the given IP address space create five subnets in such a way so that less number of IP address is wasted for each subnet and the subnets will have the following number of hosts SubnetA - 23 hostsSubnetB - 50 hostsSubnetC - 2 hostsSubnetD - 6 hostsSubnetE - 10 hostsNow find out the following for each subnet: a) Network ID b) Broadcast address c) First usable IP address d) Last usable IP address e) Subnet mask Here, while solving the question make sure you are saving IP addresses. For example, SubnetA needs 23 hosts so in SubnetA you can allocate maximum 30 hosts. Follow the table for all the allowed number of hosts and required number of host bits for each subnet: Name of Subnet Maximum number hosts you can allocate Length of Host bits in the IP address cannot exceed SubnetA 30 5-bits SubnetB 62 6-bits SubnetC 2 2-bits SubnetD 6…