calculated using a matrix determinant:Part C - Moment due to two forcesijkM =r x F =| rzryAs shown, a member is fixed at the origin, point O, and has two applied forces, F1 and F2, applied at the free end,rzF, F, Fpoint B.(Figure 3)Notice that the order of the elements of the matrixdeterminant is important; switching rows 2 and 3 of thedeterminant would change the sign of the moment frompositive to negative (or vice versa.)The forces are given by F1 = 115 Ni- 110 Nj+ 55 N k and F2 has magnitude 195 N and direction anglesa = 143.0°, B= 57.0°, and y= 75.2°. The dimensions are x1 = 1.30 m, y1 = 1.85 m, and z1 = 1.10 m.What is the moment about the origin due to the applied forces?Figure3 of 3Express the individual components of the Cartesian vector to three significant figures, separated by commas.• View Available Hint(s)vec?Mo =[i, j, k] N. mSubmitВ< Return to AssignmentProvide Feedback

Given data, The force F→1 = 115 i^-110 j^+55k^ N For force F2:- Force, F2 = 195 N α=143°, β=57° and…

As shown, a member is fixed at the origin, point O, and has two applied forces, F1 and F2, applied at the free end, point B. (Figure 3) The forces are given by F1 115 N i- 110 Nj+55 N k and F2 has magnitude 195 N and direction angles a = 143.0°, B= 57.0°, and y 75.2°. The dimensions are a1 = 1.30 m, y1 = 1.85 m, and z1 = 1.10 m. What is the moment about the origin due to the applied forces? Express the individual components of the Cartesian vector to three significant figures, separated by commas.

As shown, a member is fixed at the origin, point O, and has two applied forces, F1 and F2, applied at the free end, point B. (Figure 3) The forces are given by F1 115 N i- 110 Nj+55 N k and F2 has magnitude 195 N and direction angles a = 143.0°, B= 57.0°, and y 75.2°. The dimensions are a1 = 1.30 m, y1 = 1.85 m, and z1 = 1.10 m. What is the moment about the origin due to the applied forces? Express the individual components of the Cartesian vector to three significant figures, separated by commas.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

ENGINEERING MECHANINICS solve for the moment at A
a = 4 mb = 3.2 mc = 2 mF = {-7i+4j+12k} NSpecified axis: AF Find the following: Find the z-component of the moment of F about the specified axis. Find the x-component of the moment of F about the specified axis. Find the magnitude of the moment of F about the specified axis. Find the y-component of the moment of F about the specified axis.
use matrix to find solution for omega 3. find vD not in i+j form please.
Identification: 1. A technique used to solve for the resultant force of a non-uniform distributed load.
A line RS of 55 mm in length is inclined to HP by 30o and parallel to VP. One of its end points is above HP by 20 mm and in front of VP by 30 mm. The line is in single quadrant. Find the projections of the line RS and find out its horizontal trace.
Points for stress vs strain (in image) Assume the compressive concrete strength (f’c) is 3,000 lb/in2 (psi)Calculate a cubic function (3rd order polynomial – Ax3+Bx2+Cx+Constant)Use this function to create a function that describes the slope of the cubic function (the derivative of thecubic function). This new function allows you to calculate the tangent to any point along the curve. Thetangent is the modulus of elasticity (E). The concrete code provides a formula to calculate E for concrete. That formula is:E = 57,000√??′, where f’c is in units of psi, and E is in units of psi.Use the derivative function you calculated to locate the point on the curve where the slope of the curvematches E using the concrete code formula. Express that stress point on the curve as a percentage ofthe compressive strength of the concrete. Now, calculate the secant modulus for the test case using 1,500 psi (50% f’c) as the arbitrary point onthe curve.Assume fracture occurs at the last point…
In the figure below, two applied forces are acting at point C where there is a 120 lb and let P = 150 lb. Find the unknown forces/tensions in bar AC and BC that are reacting. Do not forget the free-body diagram, units, and vector notation.
A uniform aluminum beam 9.00 m long, weighing 300 N,rests symmetrically on two supports 5.00 m apart (Fig. ). A boyweighing 600 N starts at point A and walks toward the right. (a) In thesame diagram construct two graphs showing the upward forces FA andFB exerted on the beam at points A and B, as functions of the coordinatex of the boy. Let 1 cm = 100 N vertically and 1 cm = 1.00 m horizontally.(b) From your diagram, how far beyond point B can the boy walkbefore the beam tips? (c) How far from the right end of the beam shouldsupport B be placed so that the boy can walk just to the end of the beamwithout causing it to tip?
3. Matrixs A, B and C are m x n, n x n and n x m, respectively. The CAB matrix is sized... a. m x nb. n x nc. m x md. n x n
During a bicep curl on a bicep curl machine, I'm curling a weight stack of 100 pounds (single arm...I'm jacked like that). At this very moment, the weight stack has a moment arm of 0.12m, my elbow has an angle of 63deg, my muscle force vector has an angle of 23deg, and it attaches 3cm below my elbow joint on my radius. How much force must my bicep create right at this moment to hold the weight stack in place?
Which are the Matrices of a vector?
Given the image below, if Tcg = 52.1N, what is the moment of tension in the cord cg about the x axis?