Please answer the calculation Assume that an enzyme catalyzed reaction follows the scheme shown:k1k2ESk.1E + SE + PWhere k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM.Determine Km, Vmax, and the turnover number.Km=V max=Turnover number =

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Assume that an enzyme catalyzed reaction follows the scheme shown: k2 k1 ES E + P E + S k.1 Where k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM. %3D Determine Km, Vmax, and the turnover number. Km= V max= Turnover number =

Assume that an enzyme catalyzed reaction follows the scheme shown: k2 k1 ES E + P E + S k.1 Where k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM. %3D Determine Km, Vmax, and the turnover number. Km= V max= Turnover number =

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter21: Biochemistry

Section: Chapter Questions

Problem 26QAP

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Question

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Please answer the calculation

Assume that an enzyme catalyzed reaction follows the scheme shown:
k1
k2
ES
k.1
E + S
E + P
Where k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM.
Determine Km, Vmax, and the turnover number.
Km=
V max=
Turnover number =

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