At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10-4 P + 4.6 X 10-8 P 2 , where V is in cm3 /mol and P is in atm for Pressure between 0 and 1000 atm and ( ∂V ∂T) p = 0.0045 + 1.4 × 10−6P ( Cm3 mol .K) Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10-4 P + 4.6 X 10-8 P 2 , where V is in cm3 /mol and P is in atm for Pressure between 0 and 1000 atm and ( ∂V ∂T) p = 0.0045 + 1.4 × 10−6P ( Cm3 mol .K) Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 25PS: As a gas cools, it is compressed from 2.50 L to 1.25 L under a constant pressure of 1.01 105 Pa....
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Question
At 25°C the molar volume of water V is given by:
V = 18.066 – 7.15 X 10-4 P + 4.6 X 10-8 P
2
,
where V is in cm3
/mol and P is in atm for Pressure between 0 and 1000 atm and
(
∂V
∂T)
p
= 0.0045 + 1.4 × 10−6P (
Cm3
mol .K)
Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to
1000 atm and the change in its internal energy.
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