At 800 K, hydrogen iodide can decompose into hydrogen and iodine gases. 2HI(9) =12(9) +H2(9) At this temperature, K = 0.0169. What are the partial pressures at equilibrium of the hydrogen and iodine if initially a sealed flask at 800 K contains only HI at a pressure of 0.242 atm? Partial pressure of hydrogen = atm Partial pressure of iodine = atm

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 36QAP: At a certain temperature, K=0.29 for the decomposition of two moles of iodine trichloride, ICl3(s),...
icon
Related questions
Question

At 800 K, hydrogen iodide can decompose into hydrogen and iodine gases.

 

At this temperature, K=0.0169 . What are the partial pressures at equilibrium of the hydrogen and iodine if initially a sealed flask at 800 K contains only HI  at a pressure of 0.242 atm?

2.4)
[References]
At 800 K, hydrogen iodide can decompose into hydrogen and iodine gases.
2HI(g) = I2 (9) + H2 (g)
At this temperature, K = 0.0169. What are the partial pressures at equilibrium of the hydrogen and iodine if initially a sealed flask at 800 K contains only HI at a pressure of 0.242 atm?
Partial pressure of hydrogen =
atm
Partial pressure of iodine =
atm
Submit Answer
Try Another Version
4 item attempts remaining
Transcribed Image Text:2.4) [References] At 800 K, hydrogen iodide can decompose into hydrogen and iodine gases. 2HI(g) = I2 (9) + H2 (g) At this temperature, K = 0.0169. What are the partial pressures at equilibrium of the hydrogen and iodine if initially a sealed flask at 800 K contains only HI at a pressure of 0.242 atm? Partial pressure of hydrogen = atm Partial pressure of iodine = atm Submit Answer Try Another Version 4 item attempts remaining
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Chemical Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning