At a particular temperature, K = 1.00×102 for the reaction: H2(g) + F2(g)---> 2HF(g) In an experiment, at this temperature, 1.70 mol of H2 and 1.70 mol of F2 are introduced into a 1.12-L flask and allowed to react. At equilibrium, all species remain in the gas phase. 1a) What is the equilibrium concentration (in mol/L) of H2? 1b) What is the equilibrium concentration (in mol/L) of HF? 1c)To the mixture above, an additional 4.93×10-1 mol of H2
At a particular temperature, K = 1.00×102 for the reaction: H2(g) + F2(g)---> 2HF(g) In an experiment, at this temperature, 1.70 mol of H2 and 1.70 mol of F2 are introduced into a 1.12-L flask and allowed to react. At equilibrium, all species remain in the gas phase. 1a) What is the equilibrium concentration (in mol/L) of H2? 1b) What is the equilibrium concentration (in mol/L) of HF? 1c)To the mixture above, an additional 4.93×10-1 mol of H2
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.25PAE
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Hi, i need help with this. i would apprecite it if the solution was handwritten rather than types for more understanding.
At a particular temperature, K = 1.00×102 for the reaction:
| H2(g) + F2(g)---> 2HF(g) |
In an experiment, at this temperature, 1.70 mol of H2 and 1.70 mol of F2 are introduced into a 1.12-L flask and allowed to react. At equilibrium, all species remain in the gas phase.
1a) What is the equilibrium concentration (in mol/L) of H2?
1b) What is the equilibrium concentration (in mol/L) of HF?
1c)To the mixture above, an additional 4.93×10-1 mol of H2 is added.
What is the new equilbrium concentration (in mol/L) of HF?
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