A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at fị = 2.59 s given the details for the motion of particles 1, 2, and 3. particle 1: m = 1.81 kg, vi (1) = (5.65 m/s) + (0.321 m/s² ) × t particle 2: m2 = 3.53 kg, v2 (t) = (8.93 m/s) + (0.651 m/s²) × t particle 3: m3 = 4.37 kg, v3 (1) = (7.21 m/s) + (0.237 m/s²) × t particle 4: m4 = 4.55 kg V4 = m/s * TOOLS x10

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
Problem 53CP
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A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not
interact with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.59 s given the details for the motion
of particles 1, 2, and 3.
particle 1:
m1 = 1.81 kg,
v1 (t) = (5.65 m/s) + (0.321 m/s²) × t
particle 2:
m2 = 3.53 kg, v2 (t) = (8.93 m/s) + (0.651 m/s²) × t
particle 3: m3 = 4.37 kg,
v3 (t) = (7.21 m/s) + (0.237 m/s²) × t
particle 4:
m4 = 4.55 kg
V4 =
m/s
E TOOLS
x10
Transcribed Image Text:A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.59 s given the details for the motion of particles 1, 2, and 3. particle 1: m1 = 1.81 kg, v1 (t) = (5.65 m/s) + (0.321 m/s²) × t particle 2: m2 = 3.53 kg, v2 (t) = (8.93 m/s) + (0.651 m/s²) × t particle 3: m3 = 4.37 kg, v3 (t) = (7.21 m/s) + (0.237 m/s²) × t particle 4: m4 = 4.55 kg V4 = m/s E TOOLS x10
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