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= = Av Ephoton = hv KE = hv – c = 2.998 × 108 m/s h=6.626 x10-34 J.s = 6.63 x 10-34 kg m/s Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding energy or work function () for Cs. Calculate the wavelength (in nm) of a photon that could remove an lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 × 10 2º J.

= = Av Ephoton = hv KE = hv – c = 2.998 × 108 m/s h=6.626 x10-34 J.s = 6.63 x 10-34 kg m/s Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding energy or work function () for Cs. Calculate the wavelength (in nm) of a photon that could remove an lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 × 10 2º J.

Principles of Instrumental Analysis
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter18: Raman Spectroscopy
Section: Chapter Questions
Problem 18.5QAP
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FIVE STAR. XX XX Worksheet 10: deBroglie and Heisenberg c = Av Ephoton = hv CHEM 130 1. Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the KE = hv – & c = 2.998 × 108 m/s h=6.626 ×10-34 J.s = 6.63 x 10-34 kg•m²/s energy or work function (0) for Cs. Calculate the wavelength (in nm) of a photon that could remove an Fall 2021 surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 x 10 20 J. XX XXXXX XXXXXXX XXXXX
Transcribed Image Text:FIVE STAR. XX XX Worksheet 10: deBroglie and Heisenberg c = Av Ephoton = hv CHEM 130 1. Photoelectric effect follow-up: The minimum energy needed to remove one mole of electrons from the KE = hv – & c = 2.998 × 108 m/s h=6.626 ×10-34 J.s = 6.63 x 10-34 kg•m²/s energy or work function (0) for Cs. Calculate the wavelength (in nm) of a photon that could remove an Fall 2021 surface of cesium (Cs) metal is 187.9 kJ. As discussed in class, this is equivalent to the electron binding lectron from the surface of cesium with an acquired kinetic energy (KE) of 3.96 x 10 20 J. XX XXXXX XXXXXXX XXXXX
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