b Answered:E Enthalpy - Chemistry x 101 Chem101 app.101edu.co Submit Question 21 of 29 Using the equations Si(s) + 2 Cl2 (g) → SICI4 (s) AH° = -640.1 kJ/mol 2 Fe (s) + 3 Cl2 (g) → 2 FeCl3 (s) AH° = -800.0 kJ/mol Determine the enthalpy for the reaction 3 SiCl: (s) + 4 Fe (s) → 4 FECI3 (s) + 3 Si (s). kJ/mol 1 3 4 8 9. x 100 +/- 8:49 PM O Type here to search 12/8/2019 LO

Physical Chemistry
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ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
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Problem 2.79E: The enthalpy of combustion of diamond is -395.4 kJ/mol. C s, dia O2 g CO2 g Determine the fH of C...
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b Answered:E Enthalpy - Chemistry x
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Question 21 of 29
Using the equations
Si(s) + 2 Cl2 (g) → SICI4 (s) AH° = -640.1 kJ/mol
2 Fe (s) + 3 Cl2 (g) → 2 FeCl3 (s) AH° = -800.0 kJ/mol
Determine the enthalpy for the reaction
3 SiCl: (s) + 4 Fe (s) → 4 FECI3 (s) + 3 Si (s).
kJ/mol
1
3
4
8
9.
x 100
+/-
8:49 PM
O Type here to search
12/8/2019
LO
Transcribed Image Text:b Answered:E Enthalpy - Chemistry x 101 Chem101 app.101edu.co Submit Question 21 of 29 Using the equations Si(s) + 2 Cl2 (g) → SICI4 (s) AH° = -640.1 kJ/mol 2 Fe (s) + 3 Cl2 (g) → 2 FeCl3 (s) AH° = -800.0 kJ/mol Determine the enthalpy for the reaction 3 SiCl: (s) + 4 Fe (s) → 4 FECI3 (s) + 3 Si (s). kJ/mol 1 3 4 8 9. x 100 +/- 8:49 PM O Type here to search 12/8/2019 LO
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