I need help sloving for problem B. I am using the second law equation and can't seem to get it right. It is not a X10^(#) answer. They want it as a L/(mol*s) a A plot of 1/[A] versus time for the hypothetical reactionА — В +Сyields a straight line. What is the order of the reaction?first-ordersecond-orderO third-orderO fourth-orderb If it took 24 s for the concentration to drop 65 percent from its initial value of 0.5(rate constant for the reaction?Rate constant = |0.045L/(mol · s)An error has been detected in your answer. Check for typos,miscalculations etc. before submitting your answer.

The given reaction is of second order.

Answered: b If it took 24 s for the concentration…

b If it took 24 s for the concentration to drop 65 percent from its initial value of 0.50 rate constant for the reaction? Rate constant =|0.045 L/(mol - s)

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter11: Chemical Kinetics

Section: Chapter Questions

Problem 6RQ: Derive expressions for the half-life of zero-, first-, and second-order reactions using the...

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