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BACKGROUND: A researcher is conducting a study on features of learning technology and has chosen to examine the effects of three different learning methods on performance in a graduate course (i.e., Audio-supplement, visual-supplement, no supplement on final exam grade). A representative sample was selected and randomly assigned to each of the three study methods. The researcher hypothesized that those who received A/V supplemented materials would perform significantly better on the exam.ANALYSIS: In comparing sample means, it turns out that the test statistic in this study is F (2, 149) = 1.7; the critical value for the test statistic is F = 2.1. What decision should the researcher make about the null hypothesis?A) Fail to reject the null hypothesis B) Reject the null hypothesis C) Not enough information to make this decision. Explain how you came to this conclusion.

Question

BACKGROUND: A researcher is conducting a study on features of learning technology and has chosen to examine the effects of three different learning methods on performance in a graduate course (i.e., Audio-supplement, visual-supplement, no supplement on final exam grade). A representative sample was selected and randomly assigned to each of the three study methods. The researcher hypothesized that those who received A/V supplemented materials would perform significantly better on the exam.

ANALYSIS: In comparing sample means, it turns out that the test statistic in this study is F (2, 149) = 1.7; the critical value for the test statistic is F = 2.1. What decision should the researcher make about the null hypothesis?

  1. A) Fail to reject the null hypothesis

 

  1. B) Reject the null hypothesis

 

  1. C) Not enough information to make this decision.

 

Explain how you came to this conclusion. 

check_circleAnswer
Step 1

Let µ1 and µ2 be the mean effect of Audio-supplement and visual supplement on final exam grade respectively.

The aim is to check whether those who received A/V supplemented materials would perform significantly better on the exam.

The null and the alternative hypothesis is,

H0: µ1= µ2

H1: The means are not equal.

Step 2

Decision rule:

  • If the Fcal > F(k–1,N–k) reject the null hypothesis.
  • Otherwise fail to reject the null hypothesis.

Here the critical value, F(2,149) = 1.9 and the F-statistics is 2.1.

Conclusion:

Here, the test statistic, 2.1 is greater than the critical value 1.9.

Therefore, by the decision rule, rej...

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