***please answer asap, upvote gauranteed Barrier synchronization is used to synchronize two or more processes so that all processes must finish their first phase beforeany of them is allowed to start its second phase. For two processes, we might write:process P1process P2{{/* Phase-l *//* Phase-| */signal(s1);signal(s2);wait(s2);wait(s1);/* Phase-Il *//* Phase-Il */}},Where s1 and s2 are two binary semaphores, both initialized toNow, suppose there are four processes P1, P2, P3, and P4 all being executed in two phases. The execution of the processesmust satisfy the following requirements:• Process P3 must finish phase-l first, followed by process P2, which must finish Phase-l before any of the other twoprocesses start that phase.• All phase-l's must finish before any phase-ll starts.• Phase-Il of the processes must be executed in this order: P2 first, followed by P1 or P3, and P4 last.Provide the pseudo code for your solution using semaphores. You are allowed to use any number of semaphores.N.B. You may write your answer in a different editor and then upload the document.

In software, a semaphore is defined as a data structure that is useful for solving a variety of…

Barrier synchronization is used to synchronize two or more processes so that all processes must finish their first phase befor any of them is allowed to start its second phase. For two processes, we might write: process P1 process P2 { { /* Phase-l */ /* Phase-l */ signal(s1); signal(s2); wait(s2); wait(s1); /* Phase-Il */ /* Phase-I| */ } }, Where s1 and s2 are two binary semaphores, both initialized to 0. Now, suppose there are four processes P1, P2, P3, and P4 all being executed in two phases. The execution of the processe must satisfy the following requirements: Process P3 must finish phase-l first, followed by process P2, which must finish Phase-l before any of the other two processes start that phase. • All phase-l's must finish before any phase-Il starts. • Phase-Il of the processes must be executed in this order: P2 first, followed by P1 or P3, and P4 last. Provide the pseudo code for your solution using semaphores. You are allowed to use any number of semaphores. N.B. You may write your answer in a different editor and then upload the document.

Barrier synchronization is used to synchronize two or more processes so that all processes must finish their first phase befor any of them is allowed to start its second phase. For two processes, we might write: process P1 process P2 { { /* Phase-l / / Phase-l / signal(s1); signal(s2); wait(s2); wait(s1); / Phase-Il / / Phase-I| */ } }, Where s1 and s2 are two binary semaphores, both initialized to 0. Now, suppose there are four processes P1, P2, P3, and P4 all being executed in two phases. The execution of the processe must satisfy the following requirements: Process P3 must finish phase-l first, followed by process P2, which must finish Phase-l before any of the other two processes start that phase. • All phase-l's must finish before any phase-Il starts. • Phase-Il of the processes must be executed in this order: P2 first, followed by P1 or P3, and P4 last. Provide the pseudo code for your solution using semaphores. You are allowed to use any number of semaphores. N.B. You may write your answer in a different editor and then upload the document.

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter11: Operating Systems

Section: Chapter Questions

Problem 5VE

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As soon as an interrupt is received, the CPU suspends the process that is presently running and continues to serve the interrupted process. Justification for suspending an already-running procedure As an alternative, why can't we just complete the currently running process and deal with the interrupt afterwards?
An example of a MISD machine might be something like a systolic array, which is a kind of array. A pipeline network or "wavefront" of data processing units that is organised as a network might be referred to as a systolic array. Since the receipt of new data is what initiates execution, none of these components need the employment of a program counter in order to function properly. Each individual unit in a timed systolic array computes in "lock-step," meaning that within the course of a single clock cycle, each individual unit finishes alternating stages of computation and communication.
A problem encountered in multitasking when a process is perpetually denied necessary resources is called
Computer Science Suppose for a processor system it takes 35 cycles to push and pop registers onto the stack and change the PC value to the start of the interrupt service routine (ISR) or return from it. Suppose also that the ISR software takes additional 45 cycles to store the process state before the actual ISR body begins its work, and suppose it takes the same number of cycles to restore the process state when ISR is finished. If the ISR body takes 1000 cycles, what is the percent total overhead every time the ISR is executed? If the processor is running at a 2 GHz clock frequency, how long does it take before the ISR body begins execution in nanoseconds? This is usually called the ISR latency
“Priority inversion is a condition that occurs in real time systems where a low priority process is starvedbecause higher priority processes have gained hold of the CPU”- Comment on this statement.
These two methods can interrupt processes and open pathways:
An example of a MISD device is a systolic array, a subset of arrays. Systolic arrays are networks of data processing nodes organized in a wavelike fashion, thus the name. None of these parts need the employment of a program counter since execution is started by the arrival of new data. In a timed systolic array, all of the nodes calculate and communicate in unison, or "lock-step," inside a single clock cycle.
For instance, a systolic array is a kind of array that may be thought of as a MISD device. Systolic arrays are networks of data processing nodes organized in a wavelike fashion, thus the name. None of these parts need the employment of a program counter since execution is started by the arrival of new data. In a timed systolic array, all of the nodes calculate and communicate synchronously, or "in lock-step," with one another.
Write a C program to create two processes P1 and P2. P1 takes 2 integers (x,y) and passes it to P2. P2 performs mathematical operations over receivedintegers and sends it back the output array to P1 for printing.
An operation is considered to have been successfully stopped when the central processing unit (CPU) accepts the interruption and proceeds on to the next job. If the process is already underway, then why is it impossible to halt it? Since the execution and cleaning can wait till we've resolved the problem, there's no reason not to take care of them right now.
According to Amdahl's Law, what is the maximum possible % reduction in execution time when:process A, which currently runs 19% of the time, is optimized to run faster.
An example of a MISD device is a systolic array, a subset of arrays. Systolic arrays are a networked pipeline of data processing nodes. All of these elements may function without a program counter since execution is initiated by the arrival of new data. In a timed systolic array, all of the nodes do calculations in "lock-step," with each node performing its own calculations and communicating with the others in turn over the course of a single clock cycle.