Big O notation format
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Big O notation format: Determine the runtime of the given code below.
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- /* yahtC */ #include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> void seed(int argc, char ** argv){ srand(time(NULL)); // Initialize random seed if (argc>1){ int i; if (1 == sscanf(argv[1],"%d",&i)){ srand(i); } } } void instructions(){ printf("\n\n\n\n" "\t**********************************************************************\n" "\t* Welcome to YahtC *\n" "\t**********************************************************************\n" "\tYahtC is a dice game (very) loosely modeled on Yahtzee\n" "\tBUT YahtC is not Yahtzee.\n\n" "\tRules:\n" "\t5 dice are rolled\n" "\tThe user selects which dice to roll again.\n" "\tThe user may choose to roll none or all 5 or any combination.\n" "\tAnd then the user selects which dice to roll, yet again.\n" "\tAfter this second reroll the turn is scored.\n\n" "\tScoring is as follows:\n" "\t\t*\t50 points \t5 of a kind scores 50 points.\n" "\t\t*\t45 points \tNo pairs (all unique) scores 45…int countTripletSumPermutations(int size , int* arr, int tripletSum){int count = 0 ; for(int i = 0 ; i < size - 2; i++) { if (tripletSum % arr[i] == 0) { for (int j =0 ; j < size - 1; j++) { if (tripletSum % (arr[i] * arr[j]) == 0) { int value = tripletSum /(arr[i] * arr[j]); for(int k = j + 1 ; k < size ; k++ ) if (arr[k] == value) count++ ; } } }} return count;}Exercise Fibonacci (Overflow): Write a program called FibonacciInt to list all the Fibonacci numbers, which can be expressed as an int (i.e., 32-bit signed integer in the range of [-2147483648, 2147483647]). The output shall look like: F(0) = 1 F(1) = 1 F(2) = 2 ... F(45) = 1836311903 F(46) is out of the range of int Hints: The maximum 32-bit int is kept in constant Integer.MAX_VALUE. You cannot use F(n-1) + F(n-2) > Integer.MAX_VALUE to check for overflow. Instead, overflow occurs for F(n) if (Integer.MAX_VALUE – F(n-1)) < F(n-2), i.e., no room for the next number. Try: Write a similar program for Tribonacci numbers. Exercise NumberConversion: Write a method call toRadix() which converts a positive integer from one radix into another. The method has the following header: public static String toRadix(String in, int inRadix, int outRadix) // The input and output are treated as String. Write a program called NumberConversion, which prompts the user for an input number, an input…
- 5.17 LAB: Word frequencies (JAVA) Write a program in java that reads a list of words. Then, the program outputs those words and their frequencies. The input begins with an integer indicating the number of words that follow. Assume that the list will always contain fewer than 20 words. Ex: If the input is: 5 hey hi Mark hi mark the output is: hey - 1 hi - 2 Mark - 1 hi - 2 mark - 1 Hint: Use two arrays, one array for the strings and one array for the frequencies.det.c #include <stdio.h>#include <stdlib.h>#include <string.h> double compute_det(int **a, int n) { // implement this return 0.0;} /*TEST: ./det < det.inOUTPUT:-105.00000*/int main(void) { // implement this} det.in 41 2 3 45 2 3 12 5 0 13 2 4 2c++complete and change #include <iostream>using namespace std; int sumbyrow(int* m, int ncol, int row){int total = 0;for (int i = 0 i < ncol; i++) {total += m[row * ncol + i];}return total; } int sumBCol(int* m, int nrow, int ncol, int col){int total = 0;for (int j = 0; < j nrow; j++) {total += m[j * ncol + col]; }return total;}int sumBYLeftDiag(int* m, int ncol){int total = 0;for (int i = 0, j = ncol - 1; i < ncol && j >= 0; i++, j--) {total += m[i * ncol + j];}return total;}bool hasDuplicates(int* m, int row) {int flatArray[row * row];int k = 0for (int i = 0; i < row; i++) {for (int j = 0; j < row; j++) {flatArray[k++] = m[i * row + j]; }}for (int i = 0; i < (row * row); i++) {for (int j = i + 1; j < (row * row); j++) {if (flatArray[i] == flatArray[j])return true; }}return flase;} bool isMagicMatrix(int* m, int nrow, int ncol) { if (hasDuplicate(m, nrow), int ncol{return false; }if (sumByleftDiag(m, nrow) != sumByRightDiag(m, nrow)) {return…
- def tpr(tp, fn): # TODO return def TEST_tpr(): tpr_score = tpr(tp=100, fn=1) todo_check([ (np.isclose(tpr_score,0.99009, rtol=.01),"tpr_score is incorrect") ]) TEST_tpr() garbage_collect(['TEST_tpr'])int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *pIn Java Write an application that inputs five numbers, each between 10 and 100, inclusive. As each number is read, display it only if it’s not a duplicate of a number already read. Provide for the “worst case,” in which all five numbers are different. Use the smallest possible array to solve this problem. Display the complete set of unique values input after the user enters each new value. Rough output in screenshot
- in java Integer numVals is read from input and integer array userCounts is declared with size numVals. Then, numVals integers are read from input and stored into userCounts. If the first element is less than the last element, then assign Boolean firstSmaller with true. Otherwise, assign firstSmaller with false. Ex: If the input is: 5 40 22 41 84 77 then the output is: First element is less than last element 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 import java.util.Scanner; public class UserTracker { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); intnumVals; int[] userCounts; inti; booleanfirstSmaller; numVals=scnr.nextInt(); userCounts=newint[numVals]; for (i=0; i<userCounts.length; ++i) { userCounts[i] =scnr.nextInt(); } /* Your code goes here */ if (firstSmaller) { System.out.println("First element is less than last element"); } else { System.out.println("First element is not less…def makeRandomList(size): lyst = [] for count in range(size): while True: number = random.randint(1, size) if not number in lyst: lyst.append(number) break return lyst give me proper analysis of this code and Big Ojava: Run length coding is a method to represent a string in a more compact manner. Each character that occurs more than 2 times in a row is represented by the character and a number following it. Two examples are: "abba" → "abba""abcccbbbba" → "abc3b4a"Write a function that calculates how many characters the encoded string is shorter than the original.