You perform a ten-fold serial dilution of a bacterial culture to determine the number of colony forming units (CFU) per mL in the culture. You then do a plate count with these growth results (no. of colonies): 1:10: too many to count; 1:100 too many to count; 1:1,000: 126 colonies; 1:10,000 14 colonies; 1:100,000: no growth The number of CFU per mL in the original culture was: 1 ml 1 ml 1 ml 1 ml Original inoculum Dilutions 1,000 126 9 ml broth in each tube 126,000 10,000 140,000 1:10 1 ml 1:100 1 ml 1:1000 1 ml 1 ml 1:10,000 1 ml 1:100,000 1 ml
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- How would you produce a 10^-1 dilution if a 3 mL bacterial sample using the entire 3 mL volume? suppose your professor handed you a test tube with 2.0 mL of an E. coli broth culture in it and told you to make a 10^-1 dilution of the entire culture. Explain how you would do this. Show your calculations.In a serial dilution, you plate 1 ml of a 1/1000 dilution of a bacterial culture and find 25 colonies the next day. What was the concentration of cells in the original culture? A) 25 cells/ml B) 0.000025 cells/ml C) 25,000 cells/ml D) 26 cells/ml E) 0.025 cells/mlA 10-5 dilution is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 278 colony forming units grow on the plate. How many bacteria are in a single mL of the original culture? Express your answer to two decimal places using scientific notation. In scientific notation 540 would be written as 5.40*10^2. Since only 0.1 mL is put on the plate, this counts as an extra dilution!!! Any time less than 1 mL is transferred, a dilution is being performed. Any time more than 1 mL is transferred, a concentration is being performed. Include the trailing zero so there are two decimal places Canvas expects a single digit before the decimal point. 5.40*10^2 is how Canvas expects 540 to be formatted in scientific notation 54.00*10^1 would be marked wrong. 0.54*10^3 would be marked wrong. A 10-5 dilution is performed on a culture of bacteria in order to perform viable plate counts. From the…
- 1 mL of a juice sample is taken and diluted in 9 mL culture medium, subsequently, this suspension is analyzed in the Petroff-Hausser chamber, determines that the total number of bacteria found is 44 bacteria per square, if the chamber has 25 squares, how many bacteria are in the chamber? initial juice sample?You were asked to prepare a dilution series of a bacterial culture where only 3 tubes will be used (all with 5 mL total solution). Draw a schematic diagram to make tube 1 have a 10-2 dilution, tube 2 have 10-3 dilution, and tube 3 to have 10-5 dilution You were instructed to dilute an antibiotic solution 1/10, redilute 1/25, and again 1/50, then you need to make 100mL of each dilution. How would you go about preparing this dilution series? (Present your answer in a schematic diagram)When counting bacteria, the difference between the standard plate (STP) count and a direct microscopic count is that STP counts the number of ......... ...cells only.
- A serial dilution of a bacterial culture yields the following number of colonies. Which plate(s) should be used to determine the original cell density? Plate A Plate B Plate C Plate D Plate E Dilution Factor 10-5 10-6 10-7 10-8 10-9 # of Colonies Too many to count 850 456 80 14 Group of answer choices All of these choices A & B D & E E None of these choices A B & C D B C & D CComparing the different methods for counting bacterial cells, which of the following is FALSE? A. The serial dilution methods counts only viable cells. B. The turbidity method indirectly measures the number of cells observing how much light goes through a broth sample C. The turbidity method uses a spectrophotometer D. The direct microscopic method counts only viable cells E. The direct microscopic method counts both viable and non-viable cellsWhat conclusion would you draw if the numbers of bacterial colonies in were the same on the control plate and the treatment plate? Explain your reasoning.
- You perform a quadrant streak and isolate a single colony which contains two distinct species of bacteria. You repeat this with the same results. Provide a possible explanation for this result that does not involve contamination of the sample.You are testing ground beef to determine how many bacteria are present per gram of meat. You place 1 gram of meat in sterile water, mix vigorously, and then do serial dilutions as shown below. You inoculate a plate with 0.1 ml of the sample from the last tube. The next day you count 122 colonies. How many bacteria/ml were in the undiluted sample?You prepared 10-7, 10-8, and 10-9 dilutions of a bacterial suspension in sterile saline. Then you plated 0.15mL if each dilution onto each of 3 plates of nutrient agar. After incubation, the colonies were way too numerous to counton the plates prepared from the 10-7 dilution. The plates from the 10-8 dilution had 355, 360, and 350 colonies. The platesfrom the 10-9 dilution had 115, 117, and 118 colonies. Determine the concentration of colony forming units (cfu/mL) inthe original bacterial suspension