Block 1 (m1 = 8 kg) is resting on top of block 2 (m2 = 4 kg) on the surface of a table. A rope pulls vertically up on block 1 with force 12 N. On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. (use g = 10 m/s2). Remember that the x-component is the "i" component and the y-component is the "j" component. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Tries 0/2 Tension force on block 1 by Rope T1R = i + j N Tries 0/2 Normal force on block 1 by block 2 N12 = i + j N Tries 0/2
Block 1 (m1 = 8 kg) is resting on top of block 2 (m2 = 4 kg) on the surface of a table. A rope pulls vertically up on block 1 with force 12 N. On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. (use g = 10 m/s2). Remember that the x-component is the "i" component and the y-component is the "j" component. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Tries 0/2 Tension force on block 1 by Rope T1R = i + j N Tries 0/2 Normal force on block 1 by block 2 N12 = i + j N Tries 0/2
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter6: Applications Of Newton’s Laws Of Motion
Section6.4: Kinetic And Rolling Friction
Problem 6.7CE: What forces act on you as you walk across a room? Draw a free-body diagram showing all of them....
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Block 1 (m1 = 8 kg) is resting on top of block 2 (m2 = 4 kg) on the surface of a table. A rope pulls vertically up on block 1 with force 12 N.
On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. (use g = 10 m/s2).
Remember that the x-component is the "i" component and the y-component is the "j" component.
FORCES on BLOCK 1
Weight force on block 1 by Earth
W1E = i + j N
Tries 0/2 |
Tension force on block 1 by Rope
T1R = i + j N
Tries 0/2 |
Normal force on block 1 by block 2
N12 = i + j N
Tries 0/2 |
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