Bob selects independent random samples from two populations and obtains the values pi 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: - 0.200 ± 1.96(0.048) = 0.200 ±0.094. Note that 0.048 is called the estimated standard error of ĝ1 – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi + p2

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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Bob selects independent random samples from
two populations and obtains the values pi
0.700 and p2 = 0.500. He constructs the 95%
confidence interval for p1 – P2 and gets:
|
0.200 ± 1.96(0.048) = 0.200 ±0.094.
Note that 0.048 is called the estimated standard
error of ĝ1 – p2 (the ESE of the estimate).
Tom wants to estimate the mean of the success
rates:
Pi + P2
2
(a) Calculate Tom's point estimate.
(b) Given that the estimated standard er-
ror of (p1 + P2)/2 is 0.024, calculate
the 95% confidence interval estimate of
(p1 + p2)/2. Hint: The answer has our
usual form:
Pt. est. + 1.96 × ESE of the estimate.
Transcribed Image Text:Bob selects independent random samples from two populations and obtains the values pi 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: | 0.200 ± 1.96(0.048) = 0.200 ±0.094. Note that 0.048 is called the estimated standard error of ĝ1 – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (p1 + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (p1 + p2)/2. Hint: The answer has our usual form: Pt. est. + 1.96 × ESE of the estimate.
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