Boron trichloride is prepared from the following reaction: 2B2O3+6Cl2+3C⟶4BCl3+3CO22BX2OX3+6ClX2+3C⟶4BClX3+3COX2 3.387 g B2O3 is mixed with 9.504 g Cl2 and 2.509 g of C. Answer the following questions. What is the limiting reagent?   What is the theoretical yield of boron trichloride in grams?     What is the total mass of excess reagents in grams?

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