By using this table answer this question in SQL: Show the department id, department name and the number of employees working in any department which has less than 4 employees JOB_HISTORYJOBSPF' EMPLOYEE_IDP' START_DATE* END_DATEJOB_IDDEPARTMENT_IDP JOB_ID* JOB_TITLEMIN_SALARYMAX_SALARY NUMBER (6)NUMBER (0)VARCHAR2 (10 BYTE)VARCHAR2 (35 BYTE)DATEDATENUMBER (8)VARCHAR2 (10 BYTE)NUMBER (4)JOB_ID_PKO IDX_JOB_TITLEJHIST_EMP_ID_ST_DATE_PKO JHIST_JOB_IXJHIST_EMPLOYEE_IXO JHIST_DEPARTMENT_IXDEPARTMENTSDEPARTMENT_IDDEPARTMENT_NAMEMANAGER_IDNUMBER (4)VARCHAR2 (30 BYTE)FNUMBER (8)NUMBER (4)EMPLOYEESLOCATION_IDEMPLOYEE_IDFIRST_NAME* LAST NAMEU' EMAILNUMBER (6)VARCHAR2 (20 BYTE)VARCHAR2 (25 BYTE)VARCHAR2 (25 BYTE)VARCHAR2 (20 BYTE)DEPT_ID_PKDEPT_LOCATION_IXPHONE_NUMBERHIRE_DATEJOB_IDSALARYDATEVARCHAR2 (10 BYTE)LOCATIONSNUMBER (8.2)COMMISSION_PCTFMANAGER_IDFDEPARTMENT_IDNUMBER (2.2)NUMBER (8)NUMBER (4)LOCATION_IDSTREET_ADDRESSPOSTAL_CODE* CITYNUMBER (4)VARCHAR2 (40 BYTE)VARCHAR2 (12 BYTE)STATE_PROVINCEFVARCHAR2 (30 BYTE)VARCHAR2 (25 BYTE)CHAR (2 BYTE)EMP_EMAIL_UKEMP_EMP_ID_PKO EMP_DEPARTMENT_IXO EMP_JOB_IXO EMP_MANAGER_IXO EMP_NAME_IXO IDX SALARYCOUNTRY_IDLOC_ID_PKO LOC_CITY_IXO LOC_STATE_PROVINCE_IXO LOC_COUNTRY_IxY--EMP_DETAIL S_VIEWCOUNTRIESNUMBER (6)VARCHAR2 (1O)EMPLOYEE_IDCOUNTRY_IDCHAR (2 BYTE)JOB_IDMANAGER_IDDEPARTMENT_IDCOUNTRY_NAMEVARCHAR2 (40 BYTE)NUMBER (8)FREGION_IDNUMBERNUMBER (4)COUNTRY_C_ID_PKLOCATION_IDCOUNTRY_IDFIRST_NAMELAST_NAMENUMBER (4)CHAR (2)VARCHAR2 (20)VARCHAR2 (25)NUMBER (8, 2)SALARYREGIONSCOMMISSION_PCTDEPARTMENT_NAME VARCHAR2 (30)JOB_TITLENUMBER (2, 2)P REGION_IDNUMBERVARCHAR2 (35)REGION_NAMEVARCHAR2 (25 BYTE)VARCHAR2 (30)VARCHAR2 (25)VARCHAR2 (40)VARCHAR2 (25)CITYREG_ID_PKSTATE_PROVINCECOUNTRY_NAMEREGION_NAME

Answered: By using this table answer this…

By using this table answer this question in SQL: Show the department id, department name and the number of employees working in any department which has less than 4 employees

Np Ms Office 365/Excel 2016 I Ntermed

1st Edition

ISBN:9781337508841

Author:Carey

Publisher:Carey

Chapter3: Performing Calculations With Formulas And Functions

Section: Chapter Questions

Problem 2.11CP

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Hi please fix my code so that the output matches this: Course Information: Course Number: ECE287 Course Title: Digital Systems Design Course Information: Course Number: ECE387 Course Title: Embedded Systems Design Instructor Name: Mark Patterson Location: Wilson Hall 231 Class Time: WF: 2-3:30 pm main.cpp (do not change) #include "OfferedCourse.h" int main() { Course myCourse; OfferedCourse myOfferedCourse; string courseNumber, courseTitle; string oCourseNumber, oCourseTitle, instructorName, location, classTime; getline(cin, courseNumber); getline(cin, courseTitle); getline(cin, oCourseNumber); getline(cin, oCourseTitle); getline(cin, instructorName); getline(cin, location); getline(cin, classTime); myCourse.SetCourseNumber(courseNumber); myCourse.SetCourseTitle(courseTitle); myCourse.PrintInfo(); myOfferedCourse.SetCourseNumber(oCourseNumber);…
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create database GA2gouse GA2gocreate table salesman(salesman_id int primary key, name varchar(30), city varchar(20), commission varchar(30));insert into salesman (salesman_id, name, city, commission) values (5001, 'James Hoog', 'New York', 0.15); insert into salesman (salesman_id, name, city, commission) values (5002, 'Nail Knite', 'Paris', 0.13); insert into salesman (salesman_id, name, city, commission) values (5005, 'Pit Alex', 'London', 0.11); insert into salesman (salesman_id, name, city, commission) values (5006, 'Mc Lyon', 'Paris', 0.14); insert into salesman (salesman_id, name, city, commission) values (5007, 'Paul Adam', 'Rome', 0.13); insert into salesman (salesman_id, name, city, commission) values (5003, 'Lauson Hen', 'San Jose', 0.12); Create table Customer (customer_id int primary key, cust_name varchar(30), city varchar(10), grade varchar(30), salesman_id varchar(30)(select salesman_id from salesman); why does my sql server code not work, at the customer table?
create database GA2gouse GA2gocreate table salesman(salesman_id int primary key, name varchar(30), city varchar(20), commission varchar(30));insert into salesman (salesman_id, name, city, commission) values (5001, 'James Hoog', 'New York', 0.15); insert into salesman (salesman_id, name, city, commission) values (5002, 'Nail Knite', 'Paris', 0.13); insert into salesman (salesman_id, name, city, commission) values (5005, 'Pit Alex', 'London', 0.11); insert into salesman (salesman_id, name, city, commission) values (5006, 'Mc Lyon', 'Paris', 0.14); insert into salesman (salesman_id, name, city, commission) values (5007, 'Paul Adam', 'Rome', 0.13); insert into salesman (salesman_id, name, city, commission) values (5003, 'Lauson Hen', 'San Jose', 0.12); Create table Customer (customer_id int primary key, cust_name varchar(30), city varchar(10), grade varchar(30), salesman_id int,CONSTRAINT FK_salesman_id FOREIGN KEY (salesman_id) REFERENCES salesman(salesman_id));insert into customer…
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