C++ int countVal (int A[], int size, int val) { if (size == 0) return 0; else if (A[size - 1] else - val) return 1 + countVal (A, size-1, val); return countVal (A, size - 1, val); } a. Convert this function to a tail-recursive one by adding an extra parameter b. Convert the resulting tail-recursive function into an iterative one using the transformation

C++ int countVal (int A[], int size, int val) { if (size == 0) return 0; else if (A[size - 1] else - val) return 1 + countVal (A, size-1, val); return countVal (A, size - 1, val); } a. Convert this function to a tail-recursive one by adding an extra parameter b. Convert the resulting tail-recursive function into an iterative one using the transformation

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 6PE

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Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…
For function decToBinary, write the missing parts of the recursion case. This function should return a string that stores the binary equivalent for int variable num. Example: The binary equivalent of 13 may be found by repeatedly dividing 13 by 2. So, 13 in base 2 is represented by the string "1101". Examples: decToBinary(13) -> "1101" public String decToBinary (int num) { if (num < 2) return Integer.toString(num); else return <<Missing recursive call>> + <<Missing calculation>>;}
In c++, Thanks!!! Write the simplest program that will demonstrate iteration vs recursion using the following guidelines - Write two primary helper functions - one iterative (IsArrayPrimeIter) and one recursive (IsArrayPrimeRecur) - each of which Take an array and its size as input params and return a bool such that 'true' ==> array and all elements are prime, 'false' ==> at least one element in array is not prime, so array is not prime. Print out a message "Entering <function_name>" as the first statement of each function. Perform the code to test whether every element of the array is a Prime number. Print out a message "Leaving <function_name>" as the last statement before returning from the function. Remember - there will be nested loops for the iterative function and there can be no loops at all in the recursive function. You will need to define one other helper function (IsPrimeRecur) for the recursion which should also not contain any loops to make it a…
IN C Programing Let us define the weighted sum of an integer array a[0], a[1], a[2], …, a[n-1] be a[0]*1 + a[1]*2 + a[2]*3 + …+a[n-1]*n. For example, the weighted sum of the array [5,2,6] would be 5*1+2*2+6*3 = 27. Write a recursive function that takes in an array numbers and its length n, and returns its weighter sum. You can assume n is non-negative integer. int weightedSum(int numbers[], int n) {
in C programing Write a recursive function that returns 1 if an array of size n is in sorted order and 0 otherwise. Note: If array a stores 3, 6, 7, 7, 12, then isSorted(a, 5) should return 1 . If array b stores 3, 4, 9, 8, then isSorted(b,4) should return 0.int isSorted(int *array, int n){
Implement a recursive C++ function which takes a character (ch) and a positive integer (n) and prints thecharacter ch, n times on the screen. The prototype of your function should be:void printChar (char ch, int n)For example, calling printChar('*',5) should display ***** on screen.Note: There should NOT be any loop in your function.
Please IN C++ Write the simplest program that will demonstrate iteration vs recursion using the following guidelines - Write two primary helper functions - one iterative (IsArrayPrimeIter) and one recursive (IsArrayPrimeRecur) - each of which Takes an array of integers and its size as input params and returns a bool such that 'true' ==> all elements of the array are prime, so the array is prime, 'false' ==> at least one element in array is not prime, so array is not prime. Print out a message "Entering <function_name>" as the first executed statement of each function. Perform the code to test whether every element of the array is a Prime number. Print out a message "Leaving <function_name>" as the last executed statement before returning from the function. Remember - there will be nested loops for the iterative function and there can be no loops at all in the recursive function. For the recursive function - define one other helper function (IsPrimeRecur) which…
Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B' Embed the function in a program and test it. After you have fully debugged this function, define another function named reverseCstring that takes a single argument that is a C string and modifies the argument so that it is reversed. This function will include a call to the recursive definition you did for the first part of this project, and need not be recursive. Embed this second function in a program and test it.
Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B' Embed the function in a program and test it. After you have fully debugged this function, define another function named reverseCstring that takes a single argument that is a C string and modifies the argument so that it is reversed. This function will include a call to the recursive definition you did for the first part of this project, and need not be recursive. Embed this second function in a program and test it. Turn in only this final result (with output,…
Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B'
A palindrome is a sentence that contains the same sequence of letters reading it either forwards or backwards. A classic example is '1\.ble was I, ereI saw Elba." Write a recursive function that detects whether a string is apalindrome. The basic idea is to check that the first and last letters of thestring are the same letter; if they are, then the entire string is a palindromeif everything between those letters is a palindrome.There are a couple of special cases to check for. If either the first orlast character of the string is not a letter, you can check to see if the restof the string is a palindrome with that character removed. Also, when youcompare letters, make sure that you do it in a case-insensitive way.Use your function in a program that prompts a user for a phrase andthen tells whether or not it is a palindrome. Here's another classic fortesting: '1\. man, a plan, a canal, Panama!"
/** * Write a Java function to determine if the elements of an array can be split into two groups such that the sum of one group is a non-zero multiple of 10 and the sum of the other group is odd. Your solution must use recursive backtracking. <code> * Example: * Given: {1, 2, 6, 3, 1} * Result: true because {1,2,6,1}, {3} is one possibility. * * Example: * Given: {4, 3, 5, 2} * Result: false * </code> */ public static boolean splitOdd10(int[] num) { }