Calcium carbonate (CaCO3) reacts with stomach acid (HCl, hydrochloric acid) according to the following equation:CaCO3(s)+2HCl(aq)⟶CO2(g)+H2O(l)+CaCl2(aq)Tums, an antacid, contains CaCO3. If Tums is added to 15.0 mL of a solution that is 0.500 M in HCl, how many grams of CO2 gas are produced?Express the mass to three significant figures and include the appropriate units.

Question
Asked Feb 24, 2019

 

Calcium carbonate (CaCO3) reacts with stomach acid (HCl, hydrochloric acid) according to the following equation:

CaCO3(s)+2HCl(aq)CO2(g)+H2O(l)+CaCl2(aq)

Tums, an antacid, contains CaCO3. If Tums is added to 15.0 mL of a solution that is 0.500 M in HCl, how many grams of CO2 gas are produced?
Express the mass to three significant figures and include the appropriate units.
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Expert Answer

Step 1

As we know:

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Step 2

Here we have,

Molarity of HCl = 0.500 M

Volume of HCl = 15.0 mL

 

Plugging value in above formula to calculate moles of HCl as:

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Step 3

Chemical reaction between Tums...

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