Calculate enthalpy changes for the following: a. 0.069 g of sulfur (rhombic) burns, forming SO₂(g) (AƒH° for SO₂ (g) : Enthalpy change = kJ b. 0.18 mol of HgO(s) decomposes to Hg(l) and O₂(g) (AƒH° for HgO = -90.83 kJ/mol) Enthalpy change c. 2.30 g of NH3(g) is formed from N₂(g) and excess H₂(g) (AƒH° for NH3 = -45.90 kJ/mol) Enthalpy change = KJ d. 1.46 x 10-2 mol of carbon is oxidized to CO₂(g) (AfH for CO₂ = -393.509 kJ/mol) Enthalpy change = = KJ 296.84 kJ/mol) kJ

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.33QE: The enthalpy change for the following reaction is 393.5 kJ. C(s,graphite)+O2(g)CO2(g) (a) Is energy...
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Calculate enthalpy changes for the following:
a. 0.069 g of sulfur (rhombic) burns, forming SO₂ (g) (▲ƒ H° for SO₂ (g)
2
=
Enthalpy change =
kJ
b. 0.18 mol of HgO(s) decomposes to Hg(l) and O₂(g) (^ƒH° for HgO = −90.83 kJ/mol)
Enthalpy change
c. 2.30 g of NH3(g) is formed from N₂ (g) and excess H₂(g) (AƒH° for NH3 = -45.90 kJ/mol)
Enthalpy change
KJ
=
=
kJ
296.84 kJ/mol)
-2
d. 1.46 x 10 mol of carbon is oxidized to CO₂(g) (AƒH° for CO2 = −393.509 kJ/mol)
Enthalpy change =
KJ
Transcribed Image Text:Calculate enthalpy changes for the following: a. 0.069 g of sulfur (rhombic) burns, forming SO₂ (g) (▲ƒ H° for SO₂ (g) 2 = Enthalpy change = kJ b. 0.18 mol of HgO(s) decomposes to Hg(l) and O₂(g) (^ƒH° for HgO = −90.83 kJ/mol) Enthalpy change c. 2.30 g of NH3(g) is formed from N₂ (g) and excess H₂(g) (AƒH° for NH3 = -45.90 kJ/mol) Enthalpy change KJ = = kJ 296.84 kJ/mol) -2 d. 1.46 x 10 mol of carbon is oxidized to CO₂(g) (AƒH° for CO2 = −393.509 kJ/mol) Enthalpy change = KJ
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