   Chapter 5.7, Problem 5.9CYU

Chapter
Section
Textbook Problem

Use Hess’s law to calculate the enthalpy change for the formation of CS2(ℓ) from C(s) and S(s) [C(s) + 2 S(s) → CS2(ℓ)] from the following enthalpy values. C(s) + O 2 (g) → CO 2 (g)  Δ r H 1 ∘ = − 393.5  kJ/mol-rxn S(s) + O 2 (g) → SO 2 (g)  Δ r H 2 ∘ = − 296.8  kJ/mol-rxn CS 2 ( l ) + 3 O 2 (g) → CO 2 (g) + 2 SO 2 (g)  Δ r H 3 ∘ = − 1103.9  kJ/mol-rxn

Interpretation Introduction

Interpretation:

The enthalpy change for the formation of CS2 has to be calculated.

Concept Introduction:

Hess’s law:

If a reaction proceeds in two or more reactions,ΔrH0 for the overall process is the sum of ΔrH0 values of all those reactions

Explanation

The required equation for the formation of CS2 is the reverse of 3rd

Equation i.e,

CS2+3O2CO2+2SO2

ΔrH30=ΔrH30 =+1103.9kJ/mol

2nd equation is written for 2mol of SO2, i.e,

2S2+2O22SO2

ΔrH20=rH20=-296

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