Calculate the enthalpy of the following chemical reaction: 2Fe(s) +₂02)→ Fe₂O3(s) Given: 2Fe(s) + 6H₂O(l) ---> 2Fe(OH)3(s) + 3H₂(g) Fe₂O3(s) + 3H₂O(l) ---> 2Fe(OH)3(s) 2H₂(g) + O₂(g) ---> 2H₂O(l) ΔΗ = +422 kJ ΔΗ = +389 kJ ΔΗ = +590 kJ

World of Chemistry, 3rd edition
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ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
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Chapter10: Energy
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Calculate the enthalpy of the following chemical reaction:
2Fe(s) + 3/2O2(g) → Fe₂O3(s)
Given:
2Fe(s) + 6H₂O(e) ---> 2Fe(OH)3(s) + 3H₂(g)
Fe₂O3(s) + 3H₂O(e) ---> 2Fe(OH)3(s)
2H₂(g) + O₂(g) ---> 2H₂O(l)
ΔΗ = +422 kJ
ΔΗ = +389 kJ
ΔΗ = +590 kJ
Transcribed Image Text:Calculate the enthalpy of the following chemical reaction: 2Fe(s) + 3/2O2(g) → Fe₂O3(s) Given: 2Fe(s) + 6H₂O(e) ---> 2Fe(OH)3(s) + 3H₂(g) Fe₂O3(s) + 3H₂O(e) ---> 2Fe(OH)3(s) 2H₂(g) + O₂(g) ---> 2H₂O(l) ΔΗ = +422 kJ ΔΗ = +389 kJ ΔΗ = +590 kJ
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