Calculate the Gibbs free energy (in kJ) at 25 degrees C of the following reaction using the data in the table. 4A+2B + 3C 4D + 4E AHr (kJ/mol) A 70.34 B -5.12 C 56.20 D 48.83 E -11.18 s°U/mol/K) 107.32 32.05 175.47 82.34 40.10 Report your answer to two decimal places
Calculate the Gibbs free energy (in kJ) at 25 degrees C of the following reaction using the data in the table. 4A+2B + 3C 4D + 4E AHr (kJ/mol) A 70.34 B -5.12 C 56.20 D 48.83 E -11.18 s°U/mol/K) 107.32 32.05 175.47 82.34 40.10 Report your answer to two decimal places
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.107QE: Calculate the standard Gibbs free-energy change when SO3 forms from SO2 and O2 at 298 K. Why is...
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Step 1
For a general reaction
aA + bB → cc + dD
Entropyb change
∆S°rxn =( Σv S°f )product - ( Σ vS°f )reactant
∆S°rxn = [c (S°f )c + d (S°f )d] - [a(S°f )a + b(S°f )b]
enthalpy change
∆H°rxn =( Σv ∆H°f )product - ( Σ v∆H°f )reactant
∆H°rxn = [c (∆H°f )c + d (∆H°f )d] - [a(∆H°f )a + b(∆H°f )b]
gibbs free enegy change
∆G°rxn = ∆H°rxn -T ∆S°rxn
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