Calculate the Molar Solubility of Calcium Hyroxide in the Presence of a Common Ion (CaCl2) I have included the data and some calculation that can help with solving, but I am unsure if the calculation I have provided are accurate Data: 1. Concentration of standardized HCl Solution (mol/L) = 0.0646 2. volume of saturated Ca(OH)2 with added CaCl2 solution (mL) = 25 mL 3. Buret reading, initial (mL) = 0.03 mL 4. Buret reading, final (mL) = 19.85 mL 5. Volume of HCl added (mL) = 19.82mL Calculations: 6. Amount of HCl added (mol) = 1.28x10^-3 7. Amount of OH- in saturated solution (mol) =1.28x10^-3 8. [OH-] equillirium (mol/L) =5.12x10^-2 Molar solubility of Ca(OH)2=?
Calculate the Molar Solubility of Calcium Hyroxide in the Presence of a Common Ion (CaCl2) I have included the data and some calculation that can help with solving, but I am unsure if the calculation I have provided are accurate Data: 1. Concentration of standardized HCl Solution (mol/L) = 0.0646 2. volume of saturated Ca(OH)2 with added CaCl2 solution (mL) = 25 mL 3. Buret reading, initial (mL) = 0.03 mL 4. Buret reading, final (mL) = 19.85 mL 5. Volume of HCl added (mL) = 19.82mL Calculations: 6. Amount of HCl added (mol) = 1.28x10^-3 7. Amount of OH- in saturated solution (mol) =1.28x10^-3 8. [OH-] equillirium (mol/L) =5.12x10^-2 Molar solubility of Ca(OH)2=?
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter16: Solubility And Precipitation Equilibria
Section: Chapter Questions
Problem 74AP
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Calculate the Molar Solubility of Calcium Hyroxide in the Presence of a Common Ion (CaCl2)
I have included the data and some calculation that can help with solving, but I am unsure if the calculation I have provided are accurate
Data:
1. Concentration of standardized HCl Solution (mol/L) = 0.0646
2. volume of saturated Ca(OH)2 with added CaCl2 solution (mL) = 25 mL
3. Buret reading, initial (mL) = 0.03 mL
4. Buret reading, final (mL) = 19.85 mL
5. Volume of HCl added (mL) = 19.82mL
Calculations:
6. Amount of HCl added (mol) = 1.28x10^-3
7. Amount of OH- in saturated solution (mol) =1.28x10^-3
8. [OH-] equillirium (mol/L) =5.12x10^-2
Molar solubility of Ca(OH)2=?
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