Chapter20: Applications Of Oxidation/reduction Titrations
Section: Chapter Questions
Problem 20.25QAP
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Transcribed Image Text:(d)
3-13. Distis
me Jum
4 A method of analysis yields weights for gold that are
low by 0.4 mg. Calculate the
caused by this uncertainty if the weight of gold in the
sample is
(a) 900 mg.
(c) 150 mg.
1-7. The method described in Problem 3-6 is to be used for
the analysis of ores that assay about 1.2% gold. What
minimum sample weight should be taken if the relative
error resulting from a 0.4-mg loss is not to exceed
-0.2%?
percent
relative error
(a)
(b)
(b) 600
mg.
(d) 30 mg.
3-14. Wha
stan
stam
3-15. Сог
mea
(b) -0.5%?
(a)
-0.8%?
(c)
(d) 1.2%?
3.5
3-8. The color change of a chemical indicator requires an
overtitration of 0.04 mL. Calculate the percent relative
error if the total volume of titrant is
(a) 50.00 mL.
(c) 25.0 mL.
3-9. A loss of 0.4 mg of Zn occurs in the course of an
analysis to determine that element. Calculate the per-
cent relative error due to this loss if the weight of Zn
in the sample is
(a) 40 mg.
(c) 400 mg.
3.1
3.1
(b) 10.0 mL.
3.3
2.5
(d) 40.0 mL.
Fo
(a
(E
(b) 175 mg.
(d) 600 mg.
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