Calculate the % yield when you react 20 mg of KBrO3 and produce 5 mg of KBr, assume all other reagents are in excess. Balance the equation, indicate the reactants and the products. (KBrO3 Molecular mass: 166.999 g/mol, KBr Molecular Mass: 119.002 g/mol)KBrO3 + Kl + HBr ➞ KBr + H2Oa. If you start the reaction with 20mg of KBrO3 and 20mg of Kl (molecular mass = 166.0028 g/mol) with an excess of HBr what is the limiting agent?b. How many atoms are in the 5mg of KBr?

Question
Asked Nov 5, 2019

Calculate the % yield when you react 20 mg of KBrO3 and produce 5 mg of KBr, assume all other reagents are in excess. Balance the equation, indicate the reactants and the products. (KBrO3 Molecular mass: 166.999 g/mol, KBr Molecular Mass: 119.002 g/mol)

KBrO3 + Kl + HBr ➞ KBr + H2O

a. If you start the reaction with 20mg of KBrO3 and 20mg of Kl (molecular mass = 166.0028 g/mol) with an excess of HBr what is the limiting agent?

b. How many atoms are in the 5mg of KBr?

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Step 1

A chemical reaction is symbolic representation of the conversion of substances to new substances.

In a chemical reaction; the substance which involves in conversion is said to be reactant whereas the newly formed substance is called as product. Both reactant and products must be separated by arrow.

Step 2

The balance chemical reaction is

>7 KBr + 3 12 + 3 Н20
KBГОЗ + 6 KI +6 HBr
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>7 KBr + 3 12 + 3 Н20 KBГОЗ + 6 KI +6 HBr

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Step 3

Calculate moles of KBrO3:

Molar mass of KBrO3 = 166.999 g/mol

Mass of KBrO...

mass(g)
Molar mass(g/mol)
20x 10g
Moles
1.2x 10 moles
Moles =
166.999 g/mol
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mass(g) Molar mass(g/mol) 20x 10g Moles 1.2x 10 moles Moles = 166.999 g/mol

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