Calculate the % yield when you react 20 mg of KBrO3 and produce 5 mg of KBr, assume all other reagents are in excess. Balance the equation, indicate the reactants and the products. (KBrO3 Molecular mass: 166.999 g/mol, KBr Molecular Mass: 119.002 g/mol) KBrO3 + Kl + HBr ➞ KBr + H2O a. If you start the reaction with 20mg of KBrO3 and 20mg of Kl (molecular mass = 166.0028 g/mol) with an excess of HBr what is the limiting agent? b. How many atoms are in the 5mg of KBr?

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Calculate the % yield when you react 20 mg of KBrO3 and produce 5 mg of KBr, assume all other reagents are in excess. Balance the equation, indicate the reactants and the products. (KBrO3 Molecular mass: 166.999 g/mol, KBr Molecular Mass: 119.002 g/mol)

KBrO3 + Kl + HBr ➞ KBr + H2O

a. If you start the reaction with 20mg of KBrO3 and 20mg of Kl (molecular mass = 166.0028 g/mol) with an excess of HBr what is the limiting agent?

b. How many atoms are in the 5mg of KBr?

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