Calculate the pH after addition of 1.00 mL, 20.00 mL,

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 74QAP: Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a)...
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Polyprotic acid Titration.

Consider the titration of 50.00 mL of a solution that is 0.0800 M oxalic acid. Calculate the pH after addition of 1.00 mL, 20.00 mL, and 21.00 ml of 0.2000 M KOH. 

Note: This has two equivalence regions. 

Ka1 = 5.4 x 10-2

Ka2 = 5.4 x 10-5

KOH volume added (mL) pH H+ OH [H2A] [HA-] [A2-]
1.00 (first pre-equivalence point)            
20.00 (first equivalence point)            
21.00 (second pre-equivalence point)            


Formula:

First Pre -Equivalence 
H2A = MH2AVH2A - MOHVOH/ Vtotal
HA- = MOHVOH/Vtotal
pH = pKa+ log [HA-]/[H2A]

First equivalence point
HA- = MH2AVH2A/Vtotal
H+ = √Ka1Ka2[HA-] + Ka1Kw/Ka1+ [HA-]

Second pre-equivalence point
HA- = MH2AVH2A - MOHVOH/ Vtotal
A2- = MOH(VOH-Veq1)/Vtotal
pH = pKa2+ log [A2-]/{HA-]

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