Calculate the standard enthalpy change for the reaction 2C8H18(l) + 21O2(g) → 8CO(g) + 8CO2(g) + 18H2O(l). Given: 2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l) ΔH° = –11,020 kJ/mol 2CO(g) + O2(g) → 2CO2(g) ΔH° = –566.0 kJ/mol –1.0454 × 104 kJ/mol –8,756 kJ/mol 1.1586 × 104 kJ/mol 1.0454 × 104 kJ/mol –6,492 kJ/mol
Calculate the standard enthalpy change for the reaction 2C8H18(l) + 21O2(g) → 8CO(g) + 8CO2(g) + 18H2O(l). Given: 2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l) ΔH° = –11,020 kJ/mol 2CO(g) + O2(g) → 2CO2(g) ΔH° = –566.0 kJ/mol –1.0454 × 104 kJ/mol –8,756 kJ/mol 1.1586 × 104 kJ/mol 1.0454 × 104 kJ/mol –6,492 kJ/mol
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.84QE
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Calculate the standard enthalpy change for the reaction
2C8H18(l) + 21O2(g) → 8CO(g) + 8CO2(g) + 18H2O(l).
Given:
2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l) ΔH° = –11,020 kJ/mol
2CO(g) + O2(g) → 2CO2(g) ΔH° = –566.0 kJ/mol
2C8H18(l) + 21O2(g) → 8CO(g) + 8CO2(g) + 18H2O(l).
Given:
2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l) ΔH° = –11,020 kJ/mol
2CO(g) + O2(g) → 2CO2(g) ΔH° = –566.0 kJ/mol
–1.0454 × 104 kJ/mol
–8,756 kJ/mol
1.1586 × 104 kJ/mol
1.0454 × 104 kJ/mol
–6,492 kJ/mol
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