Question

Calculate the standard reaction enthalpy for the following reaction in KJ*mol. CH4(g) + H2O(g) --> CO(g) + 3H2(g)

 

Given:

 

2H2(g) + CO(g) --> CH3OH(l) DH° = -128.3 kJ×mol-1

 

2CH4(g) + O2(g) --> 2CH3OH(l) DH° = -328.1 kJ×mol-1

 

2H2(g) + O2(g) --> 2H2O(g) DH° = -483.6 kJ×mol-1

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