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- A sample of pure sodium oxalate weighing 0.1050 g is ignited [Na2C2O4 (s) --> Na2CO3 (s) + CO (g)] and the resulting product requires 15.00 mL of a solution of H2SO4 for complete neutralization. What is the normality of the acid? MM of Na2CO3 = 106.0 g/molMM of Na2C2O4 = 134.0 g/molMM of CO = 28.01 g/molMM of H2SO4 = 98.08 g/molA solution containing AgNO3 is mixed with a solution of NaCl to form a solution that is 0.10 M in AgNO3 and 0.075 M in NaCl. What will happen once these solutions are mixed? Given: Ksp (AgCl) = 1.77 x 10-10Calculate the percent difference in the two values for the molarity of the NaOH solution by: %Difference =[M1-M2]\Mavg x100% Given: 1st value for the molarity of NaOH = 0.0647 M 2nd value for the molarity of NaOH= 0.2627 M NaOH vs H2SO4 Burette solution is NaOH and the pipette solution is 10.0 mL of 0.205 M H2SO4 Titration Initial burette reading Final burette reading Volume of NaOH consumed Average volume of NaOH Approximate 0.0 mL 31.8 mL 31.8 mL 31.7 mL Titration 1 0.0 mL 31.5 mL 31.5 mL Titration 2 0.0 mL 31.7 mL 31.7 mL To find the average volume Average volume = 31.8 mL + 31.5 mL + 31.7 mL331.8 mL + 31.5 mL + 31.7 mL3 = 31.7 mL NaOH vs CH3COOH Burette solution is NaOH and the pipette solution is 5.0 mL of Vinegar Titration Initial burette reading Final burette reading Volume of NaOH consumed Average volume of NaOH Approximate 0.0 mL 20.1 mL 20.1 mL 20.3 mL Titration 1 0.0 mL 20.9 mL 20.9 mL Titration 2 0.0 mL 20.0 mL…
- 0.5 g mixture of (0.1 N KCI and 4 points KBr) is required to 58.03 mL of 0.1 N AGNO3 to precipitate both bromide and chloride as AgCl and AgBr. Calculate the weight percentage for each of the AgCl and AgBr in a mixture if you know that the molecular weight of KCI = 74.5 and of KBr = 119 * %3DSolution A with a mass of 300 g and contains solute A is mixed with 500 g of solution B which is 40% solute B. If MW of solute B is 46 g/mol, what is its molarity after mixing? Sp gr of Solution A = 1.05, Sp gr of Solution B = 1.11Calculate the weight of pure sodium carbonate that is necessary to prepare 2.806 L of 0.223 N Na2CO3 (105.99 g/mol) from the primary-standard solid. Assume the solution is to be used for titrations in which the reaction is: CO32- + 2H+ ----> H2O + CO2 Express you answers in 3 decimal places
- A commercial vinegar was analyzed by titration to determine the percent acetic acid. Briefly, 10.00 mL of vinegar sample was diluted to 100. mL solution in volumetric flask. A 25.00 mL aliquot from the diluted vinegar required 25.55 mL of 0.1005 M NaOH to reach the phenolphthalein endpoint. Which is the correct equation between the analyte and titrant reaction? CH3COOH + NaOH → NaCH3COO + H2O 2CH3COOH + NaOH → NaCH3COO + H2O C20H14O4 + NaOH → NaC20H14O4 + H2O CH3COOH + 2NaOH → NaCH3COO + H2OA commercial product designed to prevent cut fruit from turning brown contains a mixture of ascorbic acid (HC6H7O6) and sugar (C12H22O11). Calculate the percent (w/w) of ascorbic acid in this product if a 2.1994 g portion of this product requires 36.15 mL of 0.2328 M NaOH to reach a phenolphthalein endpoint. MM HC6H7O6: 176.12 MM NaOH: 40.00Assume that the molarity of the standardized KMnO4 solution is 0.025 M and it takes 23.00 mL to reach the endpoint when titrating a dilute sample of H2O2. How many moles of H2O2 are in the diluted sample initially? Group of answer choices
- What volume of 0.10 moldm-3 sulphuric acid would be required to neutralise a mixture of 1.06 g of anhydrous sodium carbonate and 4.00 g of sodium hydroxide? (H2SO4 + 2NaOH ---> Na2SO4 + 2H2O) and (H2SO4 + Na2CO3 ® ---> Na2SO4+ H2O + CO2)A vinegar solution was prepared by diluting 25.00 mL of vinegar to 250.0 mL. From this solution, 50.00 mL portion was taken, and this required 30.00 mL of 0.1000M NaOH solution to reach neutralization end point. What is the percentage (w/v) of HOAc in the sample? Mol wt HOAc = 60.0 g/molSulfamic acid ( +H 3NSO 3 - , 97.094 g/mol) is a primary standard that can be used to standardize NaOH. +H 3NSO 3 - + OH - → H 2NSO 3 - + H 2O What is the molarity of a sodium hydroxide solution if 34.26 mL reacts with 0.3337 g of sulfamic acid?