1- The mercury present in a sample with a mass equal to 0.8142 g was precipitated with an excess of paraperiodic acid (H5I06) according to the reaction below: 5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10 H* The precipitate was filtered, washed free of precipitating agent, dried and weighed to give 0.4114 g. Calculate the % of Hg and of Hg2C12 in the sample. Data: Hg = 200.59 H = 1.008 Cl = 35.45 | = 126.90 %3D O = 16.00 %3D

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1- The mercury present in a sample with a
mass equal to 0.8142 g was precipitated
with an excess of paraperiodic acid
(H5I06) according to the reaction below:
5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10H*
The precipitate was filtered, washed free of
precipitating agent, dried and weighed to
give 0.4114 g. Calculate the % of Hg and of
Hg2Cl2 in the sample.
Data:
Hg = 200.59
H = 1.008
Cl = 35.45
| = 126.90
%3D
O = 16.00
%3D
Transcribed Image Text:1- The mercury present in a sample with a mass equal to 0.8142 g was precipitated with an excess of paraperiodic acid (H5I06) according to the reaction below: 5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10H* The precipitate was filtered, washed free of precipitating agent, dried and weighed to give 0.4114 g. Calculate the % of Hg and of Hg2Cl2 in the sample. Data: Hg = 200.59 H = 1.008 Cl = 35.45 | = 126.90 %3D O = 16.00 %3D
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