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- In the following cases rearrange the compounds as directed : (Delhi 2010)(i) In an increasing order of basic strength :C6H5NH2, C6H5 N(CH3)2, (C2H5)2NH and CH3NH2(ii) In a decreasing order of basic strength :Aniline, p-nitroaniline and p-toluidine(iii) In an increasing order of pKb values :C2H5NH2, C6H5 NHCH3, (C2H5)2NH and C6H5NH2What mass spectral fragments are formed by α cleavage of butan-2-ol,CH3CH(OH)CH2CH3 ?Treatment of isobutene [(CH3)2C=CH2] with (CH3)3CLi forms a carbanionthat reacts with CH2=O to form H after water is added to the reactionmixture. H has a molecular ion in its mass spectrum at m/z = 86, andshows fragments at 71 and 68. H exhibits absorptions in its IR spectrumat 3600−3200 and 1651 cm−1, and has the 1H NMR spectrum given below.What is the structure of H?
- N-propylbenzene, C6H5CH2CH3, contains C (sp3) -H and C (sp2) -H bonds. Its IR spectrum shows strong or medium absorptions at 3085, 3064, 3028, 2960, 2931 and 2873 cm ^ -1, as well as bands below 1600cm -1. Which statement is wrong? A.) Stretching of the C (sp3) -H bonds results in absorptions at lower wave numbers than the stretching of the C (sp2) -H bonds. B.) The absorptions at 2960, 2931 and 2873 cm ^ -1 are assigned to stretching of the C (sp3) -H bonds. C.) The absorptions at 3085, 3064 and 3028 cm ^ -1they are assigned to stretching of the C (sp2) -H bonds. D.) Each absorption can be assigned to the stretch mode of a particular bond in the propylbenzene molecule.In each case, assign the correct configuration of R or S, 1 is highest priority, 4 is lowest priority.c) FT-IR spectra of both nitro and nitrito-isomers were recorded immediately after preparation. Then small samples were exposed to heat (in oven) and their spectra were recorded again.
- Commercially available d-nitromethane (CHNO.) that was 99.9% deuterated was purchased and its Hand C {H} NMR spectra recorded. The H spectrum showed one 1:2:3:2:1 quintet at 4.33 p.p.m. whereas the C {H} spectrum showed a non-binomial septet at 62.8 p.p.m. Assign and explain this data.Treatment of isobutene [(CH3)2C = CH2] with (CH3)3CLi forms a carbanion that reacts with CH2=O to form H after water is added to the reaction mixture. H has a molecular ion in its mass spectrum at m/z = 86, and shows fragments at 71 and 68. H exhibits absorptions in its IR spectrum at 3600–3200 and 1651 cm−1, and has the 1H NMR spectrum given below. Whatis the structure of H?The leaves of the Brazilian Tree Senna multijunga contain a number of pryidine alkaloids that inhibit acetylcholinterinase. Two recentyl isolated isomeric compounds have the strcture have the strcture shown below. (NOTE: M=293) Use the mass spectral data provided to determine the precise location of the hydroxyl group in each isomer. Isomer A: EI-MS, m/z(rel. int): 222(20), 150(10), 136(25), 123(100) Isomer B:EI-MS, m/z(re;. int): 236(20), 150(10), 136(25), 123(100)