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- Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.Given the following data, calculate the 95% confidence interval. 0.452 0.453 0.448 0.456 0.458 Average = 0.4534 St. Dev. = 0.003847 1) 0.453 ± 0.004 2) 0.453 ± 0.005 3) 0.4534 ± 0.0048 4) 0.4534 ± 0.0037 5) 0.4534 ± 0.00381. 500.0 mL 0.2 M KI2. 500.0 mL 0.2 M KCl3. 500.0 mL 0.1 M K2S2O84. 500.0 mL 0.1 M K2SO45. 500.0 mL 4.0 mM Na2S2O3 (from Na2S2O3∙5H2O)pls compelete the 2nd table given the data
- a) 80°C, 40.0 kPab) 100°C, 120.0 kPac) -10°C, 66.7 kPaA. B. and C. already solved (https://www.bartleby.com/questions-and-answers/chemistry-question/a89691d6-2162-4677-b0cc-dc84fcceda08). Please answer E, F and GCircle in pencil in the image on th eirght cide of the diagram is a "2"( Pb(NO3)2 ).2. A student performed four trials to determine the molar mass of butane in Gas Laws lab. The average of the four trials was 68.7 g/mol and the standard deviation was 8.2 g/mol. How should his result be reported in a "mean +/- st. dev." format? Please make sure that you have proper number of sig figs. a) 61 g/mol to 77 g/mol b) 68.7 +/- 8.2 g/mol c) 69 +/- 8 g/mol d) 68.7 +/- 8 g/mol
- chemistry need help with correct sig-figTime(s) [X3] (mole/L) 0 0.600 500 0.481 1000 0.392 1500 0.336 2000 0.273 2500 0.230 3000 0.181 3500 0.156 4000 0.120 4500 0.106 5000 0.072 plot ln[X3] vs time plot 1/[X3] vs. timeIn Active Example 3-29 you calculated that you would have to work six weeks to earn enough money to buy a 1082.49 television. You would be working five shifts of four hours each at 9.25/hr. But, alas, when you received your first pay check, you found that exactly 23 of your earnings had been withheld for social security, federal and state income taxes, and workers compensation insurance. Taking these into account, how many weeks will it take to earn the 1082.49?
- Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466Chemistry Fraction no. Elution Vol. (mL) Abs (λ = 410) Fraction no. Elution Vol. (mL) Abs (λ = 410) 1 (PB pH 6.0) 1 0.0050 11 11 0.0041 2 2 0.0032 12 12 0.0060 3 3 0.0040 13 13 0.0064 4 4 0.0064 14 14 0.0063 5 5 0.0067 15 15 0.1109 6 6 0.0067 16 16 2.8902 7 7 0.0050 17 17 0.8500 8 (PB pH 8.0) 8 0.0049 18 18 0.2019 9 9 0.0052 19 19 0.0378 10 10 0.0050 20 20 0.0073 Use the data above to plot an elution profile, in which the absorbance is on Y-axis, and elution volume (volume = fraction number) is on X-axis. The elution profile must indicate at (1) which point the pH change occurred, (2) the fraction(s) which contain the highest myoglobin content, and (3) the maximum absorbance detected.You are absolutely the BEST. Finally someone that dosen't calculate this exercise as 836f66dgsffjgvkik!!!! I understand everything you did, but I have one question. Some experts says that km can be calculated by saying Vmax from date divided by 2 and then they find Km by going down on x-axis on the graph. But, you used the MM equation, to solve for Km. Is both method the same? Or is one of them more precise than the other? *And if theres no need to reply back after you answering my question, then I will thank you again for your help. I have more these types of exam questions that I will probably upload later, and I hope someone like you will look at it.