Given the following data, calculate the 95% confidence interval. 0.452 0.453 0.448 0.456 0.458 Average = 0.4534 St. Dev. = 0.003847 1) 0.453 ± 0.004 2) 0.453 ± 0.005 3) 0.4534 ± 0.0048 4) 0.4534 ± 0.0037 5) 0.4534 ± 0.0038
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Given the following data, calculate the 95% confidence interval.
0.452 0.453 0.448 0.456 0.458
Average = 0.4534
St. Dev. = 0.003847
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- The percentage of an additive in gasoline was measured six times with the following results: 0.13; 0.12; 0.16; 0.17; 0.20 and 0.11%. What is the 99% confidence interval for the additive percentage?Chemistry In an analysis of the content of carbohydrate present in a glycoprotein, the following results were found: 12.6, 11.9, 13.0, 12.7 and 12.5 g of carbohydrate per 100 g of protein. Taking into account that σ is unknown, the confidence interval for the average value at a 90% confidence level of the carbohydrate content is: Select one:to. 12.5 ± 0.4b. 12.5 ± 0.2c. 12.5 ± 0.5d. 12.5 ± 0.3What is the meaning of a confidence interval?
- For the numbers 116.0, 97.9, 114.2, 106.8 and 108.3, find the rangeb and 90% confidence interval for the mean.For the numbers 116.0, 97.9, 114.2, 106.8 and 108.3, find the range and 90% confidence interval for the mean.1. σ=[(Σd2)/(n-1)]½ n= number of trials d= measured value - mean σ=[(8.50mL-8.74mL)2+(9.72mL-8.74mL)2+(8.00mL-8.74mL)2/(3-1)]½ 2. σ=[(Σd2)/(n-1)]½ n= number of trials d= measured value - mean σ=[(10.69-11.52)2+(11.80-11.52)2+(12.07-11.52)2/(3-1)]½
- Calculate the 95% confidence interval for each set of data in Problem 2 if s is a good estimate of σ and has a value of *set A, 0.015; set B, 0.30 ; *set C, 0.070 ; set D, 0.20 ; *set E, 0.0090; and set F, 0.15.A group of students compiled the data shown in data table 1 below. What is the exact calculated order for H+(aq) to 2 decimal places? Exp. # [IO3-]0 (M) [I-]0 (M) [H+]0 (M) Time (s) 1 0.005 0.05 2 x 10-5 22.12 2 0.010 0.05 2 x 10-5 86.84 3 0.005 0.10 2 x 10-5 5.35 4 0.005 0.05 4 x 10-5 2.65 Question 6 options: 2.82 -2.51 3.34 2.71 -2.58 3.12 2.91 3.49 3.41 3.23 3.06 2.64Chemistry Fraction no. Elution Vol. (mL) Abs (λ = 410) Fraction no. Elution Vol. (mL) Abs (λ = 410) 1 (PB pH 6.0) 1 0.0050 11 11 0.0041 2 2 0.0032 12 12 0.0060 3 3 0.0040 13 13 0.0064 4 4 0.0064 14 14 0.0063 5 5 0.0067 15 15 0.1109 6 6 0.0067 16 16 2.8902 7 7 0.0050 17 17 0.8500 8 (PB pH 8.0) 8 0.0049 18 18 0.2019 9 9 0.0052 19 19 0.0378 10 10 0.0050 20 20 0.0073 Use the data above to plot an elution profile, in which the absorbance is on Y-axis, and elution volume (volume = fraction number) is on X-axis. The elution profile must indicate at (1) which point the pH change occurred, (2) the fraction(s) which contain the highest myoglobin content, and (3) the maximum absorbance detected.
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