Answered: Cd2+/Cd = -0.403 V. To protect Cadmium…

Cd2+/Cd = -0.403 V. To protect Cadmium from corrosion through sacrificial anodic protection, which of the following metals will be most suitable:

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 62P

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Question

Do both in 2 min. I will give u like

The reduction potential of Pt2+/Pt
= 1.21 V, Cu2+/Cu = 0.34 V, Zn2+/Zn
= -0.763 V, Pb2+/Pb = -0.126 V and
Cd2+/Cd = -0.403 V. To protect
Cadmium from corrosion through
sacrificial anodic protection, which
of the following metals will be
most suitable:
Pt
Cu
Zn
O Pb
In the reaction,P + Q
R
+SThetime taken for 75% reaction
of P is twice the time taken for
50% reaction of P.The order of the
reaction is
O 1
3

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